I think the answer is 9
It's a smaller version of the other figure.
21/3=7
27/3=9
Answer: b. 134
Step-by-step explanation:
Given : A minimum usual value of 135.8 and a maximum usual value of 155.9.
Let x denotes a usual value.
i.e. 135.8< x < 155.9
Therefore , the interval for the usual values is [135.8, 155.9] .
If interval for any usual value is [135.8, 155.9] , then any value should lie in this otherwise we call it unusual.
Let's check all options
a. 137 ,
since 135.8< 137 < 155.9
So , it is usual.
b. 134
since 134<135.8 (Minimum value)
So , it is unusual.
c. 146
since 135.8< 146 < 155.9
So , it is usual.
d. 155
since 135.8< 1155 < 155.9
So , it is usual.
Hence, the correct answer is b. 134 .
Answer:
44.4%
Step-by-step explanation:
To calculate this, we proceed as follows.
we use the probability equation below;
P(A|B) = P(A and B) / P(B)
Applying the above to the scenario at hand;
P(red | car) = P(red and car) / P(car)
P(red and car) = 40% or simply 40/100 = 0.4
P(car) = 90% = 90/100 = 0.9
P(red | car) = 0.4/0.9
P(red | car) = 0.4444 which is = 44.44% ; to the nearest tenth of a percent = 44.4%