Supplementary = 180°
Complementary = 90°
180° - 52° = 128°
90° - 52° = 38°
Hope this Helps!!
Answer:
The probability that a randomly chosen part has diameter of 3.5 inches or more is 0.9525
Step-by-step explanation:
![Mean = \mu = 3.25 inches](https://tex.z-dn.net/?f=Mean%20%3D%20%5Cmu%20%3D%203.25%20inches)
Standard deviation = ![\sigma = 0.15 inches](https://tex.z-dn.net/?f=%5Csigma%20%3D%200.15%20inches)
We are supposed to determine the probability that a randomly chosen part has diameter of 3.5 inches or more
![P(Z \geq 3.5)=1-P(z](https://tex.z-dn.net/?f=P%28Z%20%5Cgeq%203.5%29%3D1-P%28z%3C%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%29%5C%5CP%28Z%20%5Cgeq%203.5%29%3D1-P%28z%3C%5Cfrac%7B3.25-3.5%7D%7B0.15%7D%29%5C%5CP%28Z%20%5Cgeq%203.5%29%3D1-P%28z%3C-1.67%29)
Refer the z table for p value
![P(Z \geq 3.5)=1-0.0475\\P(Z \geq 3.5)=0.9525](https://tex.z-dn.net/?f=P%28Z%20%5Cgeq%203.5%29%3D1-0.0475%5C%5CP%28Z%20%5Cgeq%203.5%29%3D0.9525)
Hence the probability that a randomly chosen part has diameter of 3.5 inches or more is 0.9525
Answer:
Step-by-step explanation:
let the side of outer square=2x
then x²+x²=(20√2)²
2x²=800
x²=400
x=√400=20 in
2x=2×20=40 in
area of outer square=40²=1600 in²
area of inner square=(20√2)²=800 in²
area of shaded region A=1600-800=800 in²
Please find the attachment below for the solution...
Answer:
Adult tickets =125
Child tickets = 128
Step-by-step explanation:
Let the number of adult and children tickets sold be x and y respectively
So that
x+y= 253--------1
Since total sales/receipt is $2,771
And given that tickets for a dance recital cost $15 for adults and $7 for children hence
15x+7y= 2771-------2
Solving equation 1 and 2 simultaneously we have
x+y= 253---------------1
15x+7y= 2771----------2
Let us multiply equation 1 by 15 to get equation 3 to eliminate x and subtract equation 2 from 3
15x+15y=3795---------3
-{15x+7y= 2771----------2
0+8y=1024
8y= 1024
y= 1024/8
y= 128 tickets
So solve for x let us put y= 128 in equation 1
x+ 128=253
x=253-128
x= 125 tickets