The amount of the 12 grams sample of gold-195m having a half-life of 30.5 s that would remain after 41 s is 4.726 g
<h3>How to determine the number of half-lives </h3>
- Half-life (t½) = 30.5 s
- Time (t) = 41 s
- Number of half-lives (n) =?
n = t / t½
n = 41 / 30.5
n = 82/61
<h3>How to determine the amount remaining </h3>
- Original amount (N₀) = 12 g
- Number of half-lives (n) = 82/61
N = N₀ / 2ⁿ
N = 12 / 2^(82/61)
N = 4.726 g
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Answer:
Step-by-step explanation:
Given
velocity 
Area of cross-section 
velocity after Falling 0.19 m
conserving Flow
Answer:
9825
Step-by-step explanation:
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To find the number halfway between two numbers, you simply add them and then divide by two.
1.4142133+1.41422=2.8284333
2.8284333/2=1.41421665
That is one number in between these two. Now, we can find the number in between the middle number and the second number. This is another number in between our two numbers.
(1.41421665+1.41422)/2=1.414218325
You could keep on doing this and find tons of numbers in between these two.
Therefore, two numbers between 1.4142133 and 1.41422 are 1.41421665 and 1.414218325.
Have a wonderful day! :D
Answer:
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Step-by-step explanation:
