The diameter of the pool cover in one hundred feet
Hello!
You can use the Pythagorean Theorem
c is the hypotenuse which is the side across the right angle
a and b are the other sides
Put in the values you know
Square the numbers
Subtract 25 from both sides
Take the square root of both sides
a = 10.9
The answer is D) 10.9 centimeters
Hope this helps!
Answer:
The answer is below
Step-by-step explanation:
A polynominal function that describes an enclosure is v(x)=1500x-x2 where x is the length of the fence in feet what is the maximum area of the enclosure
Solution:
The maximum area of the enclosure is gotten when the differential with respect to x of the enclosure function is equal to zero. That is:
V'(x) = 0
V(x) = x(1500 - x) = length * breadth.
This means the enclosure has a length of x and a width of 1500 - x
Given that:
v(x)=1500x-x². Hence:
V'(x) = 1500 -2x
V'(x) = 0
1500 -2x = 0
2x = 1500
x = 1500 / 2
x = 750 feet
The maximum area = 1500(750) - 750² = 562500
The maximum area = 562500 feet²
Use your SOH CAH TOA functions to find the missing legs. Do Sin(53.1) and that is equal to opposite (PU) over hypotenuse (UG) so to solve for the PU leg just set up an equation that says sin(53.1)=PU/36 so then you can just multiply the 36 over and that gives you the leg. To find PG do adjacent over hypotenuse so Cosine, cos(53.1)=PG/36 and again just multiply over the 36 and that gives you PG