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3 years ago

What is the equation for y=-2+3 and y=1/3x-1?

1 answer:

Crank3 years ago

4 0

So y=-2+3 means y=3-2
y=1

so then subsitute 1 for y and solve
1=1/3x-1
add 1 to both sides
2=1/3x
multiply boht sides by 3
6=x
so x=6
y=1

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How many solutions does the equation have?

SSSSS [86.1K]

Let's solve and find out.

4(2n - 4) + 3 = 8n - 19
8n - 16 + 3 = 8n - 19
8n - 13 = 8n - 19
-13 = -19

-13 and -19 are not equal, so the equation has no solutions.

Answer:
A. 0

6 0

3 years ago

Read 2 more answers

1) A scuba diver dives beneath the surface of the water 34 feet. He swims up 13 feet closer to the surface, then swims back down

Nataliya [291]

1. 0 - 34 + 13 - 5 = -26.....26 ft below the surface

2. y = 15x + 50
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3 years ago

Using the quadratic formula to solve 4x2 – 3x + 9 = 2x + 1, what are the values of x?

yaroslaw [1]

Answer:

The value of x is:

$x=\dfrac{5\pm \sqrt{103}i}{8}$

Step-by-step explanation:

we have to use the quadratic formula to solve for x.

The equation is given as:

$4x^2-3x+9=2x+1$

which could also be written as:

$4x^2-3x+9-2x-1=0\\\\4x^2-3x-2x+9-1=0\\\\\\4x^2-5x+8=0$

The quadratic formula for the quadratic equation of the type:

$ax^2+bx+c=0$ is given as:

$x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

Here we have:

a=4, b=-5 and c=8.

Hence, by the quadratic formula we have:

$x=\dfrac{-(-5)\pm \sqrt{(-5)^2-4\times 8\times 4}}{2\times 4}\\\\x=\dfrac{5\pm \sqrt{25-128}}{8}\\\\\\x=\dfrac{5\pm \sqrt{103}i}{8}$

Hence, the value of x is:

$x=\dfrac{5\pm \sqrt{103}i}{8}$

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3 years ago

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Afina-wow [57]

And....?

There's not enough info for me to answer.

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3 years ago

1/6d + 2/3 = 1/4(d-2)

KonstantinChe [14]

$\frac{1}{6}d+\frac{2}{3}=\frac{1}{4}(d-2) \\ \\ \frac{d}{6}^{(2}}+\frac{2}{3}^{(4}=\frac{d-2}{4}^{(3} \\ \\ 2d+8=3(d-2) \\ \\ 2d+8=3d-6 \\ \\ 2d-3d=-6-8 \\ \\ -d=-14 \\ \\ \boxed{d=14}$

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3 years ago