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Dennis_Churaev [7]

3 years ago

13

A tailor needs three pieces of fabric, 1.68 yards long, 1.5 yards long, and 1.26 yards long. Estimate how many yards of material

he should buy to the nearest yard.

1 answer:

Allisa [31]3 years ago

5 0

He should buy 5 yards of material

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How do I do A and B? Please tell me step by step! Thanks :)

sergeinik [125]

Formula

P = 2L + 2W

Givens

P = 106

L = 29

W = ????

Solve

106 = 2* 19 + 2(W)

106 = 58 + 2W Subtract 58

106 - 58 = 2W

48 = 2*W Divide by 2

48/2 = W

W = 24 <<<< Answer

4 0

3 years ago

Supplementary angles angles are two angles whose measures have a sum of ___. complementar angles are two angles measures have a

Amiraneli [1.4K]

supplementary angles are two angles whose measures have a sum of 180 degrees. complementary angles are two angles whose measures have a sum of 90 degrees.

might want to check your spelling

7 0

3 years ago

The height of a triangle is 2 less than 5 times its base. If the base of the triangle is xfeet, and the area is 12 square feet,

Reil [10]

Answer:

$5B^{2} - 12B +10B - 24 = 0\\\\\$ Base of triangle = 2.4 Feet and Height of triangle = 10 feet.

Step-by-step explanation:

This problem can be solved by using formula to calculate area of triangle.

<u>Area of triangle = 1/2*(base*height)</u>

given

Let base of triangle B

height if triangle H

according to problem

The height of a triangle is 2 less than 5 times its base

mathematically it can be expressed as

H = 5*B - 2

Given area of triangle= 12 sq feet

Area of triangle = 1/2*(base*height)

=> 12 = 1/2* {B*(5*B-2)}

=> 24 = 5B^2 - 2B

$5B^{2} - 12B +10B - 24 = 0\\\\\$ which is a quadratic equation

It can be solved as given below

$5B^{2} +10B - 12B - 24 = 0\\\\\=>5B(B +2) -12(B +2) = 0\\=> (5B - 12) (B +2) = 0\\5B - 12 = 0 or B + 2 = 0\\Hence B = 12/5 \ or \ B = -2\\\\$

Since for side of triangle B cannot be negative number hence B= 12/5 = 2.4

Therefore height of triangle = 5*B - 2 = 5*2.4 - 2 = 12 - 2 = 10

Base of triangle = 2.4 Feet and Height of triangle = 10 feet.

Equation which models this situation is

$5B^{2} - 12B +10B - 24 = 0\\\\\$

6 0

3 years ago

(3-4 +5-3)-²<br><br>help me<br><br>

Luba_88 [7]

Answer:

1

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

(X^2+x-6)(2x^2+4x) factor completely

MissTica

Answer:

$2x\left(x-2\right)\left(x+3\right)\left(x+2\right)$

Step-by-step explanation:

Lets go ahead and take a step by step approach to solving your problem.

First we must start by factoring $x^2+x-6$ .

To do this, we must break the expression into groups! Although I will also provide a definition to help you understand! For $ax^2+bx+c$ we need to find u, v > $u\cdot \:v=a\cdot \:c$ and $u+v=b$ which we will group into $\left(ax^2+ux\right)+\left(vx+c\right)$ .

The values we have are... $a=1,\:b=1,\:c=-6$ and $u\cdot v=-6,\:u+v=1$ .

Now we need the factors of 6 which are 1, 2, 3 and 6. We also need the negative factors which you get simply by multiplying the positives by -1 or just reversing them.

Now we need to check for every two factors if u + v = 1.

$\mathrm{Check}\:u=1,\:v=-6: \:u\cdot v=-6,\:u+v=-5 \Rightarrow \mathrm{False}$

$\mathrm{Check}\:u=2,\:v=-3: \:u\cdot v=-6,\:u+v=-1 \Rightarrow \mathrm{False}$

$\mathrm{Check}\:u=3,\:v=-2: \:u\cdot v=-6,\:u+v=1 \Rightarrow \mathrm{True}$

$\mathrm{Check}\:u=6,\:v=-1: \:u\cdot v=-6,\:u+v=5 \Rightarrow \mathrm{False}$

Therefore $u=3,\:v=-2$ .

Now we want to $\mathrm{Group\:into\:}\left(ax^2+ux\right)+\left(vx+c\right)$ . Which is $\left(x^2-2x\right)+\left(3x-6\right)$ .

Now we must factor x from $x^2-2x$ .

Lets apply the exponent rule of $a^{b+c}=a^ba^c$ which means $x^2=xx$ .

Therefore we now have xx - 2x. Lets factor out the common term of x to get x(x - 2).

Now factor 3 out of $3x-6$ .

Rewrite 6 as 3 * 2. $3x-3\cdot \:2$ .

Now factor out the common term of 3 > $3\left(x-2\right)$ .

$x\left(x-2\right)+3\left(x-2\right)$ > Factor out the common term of x - 2 > $\left(x-2\right)\left(x+3\right)$ .

Now lets factor $2x^2+4x$ .

Apply the previous exponent rule of $a^{b+c}=a^ba^c$ > $x^2=xx$ > $2xx+4x$ .

Now rewrite 4 as 2 * 2 > $2xx+2\cdot \:2x$ .

Now factor out the common term of 2x to get 2x(x + 2).

Combine it all and we get $2x\left(x-2\right)\left(x+3\right)\left(x+2\right)$ .

Hope this helps!

7 0

3 years ago