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Galina-37 [17]
3 years ago
8

How to solve an absolute value equation ?

Mathematics
1 answer:
Triss [41]3 years ago
3 0

Step-by-step explanation:

first you need to know

|ax+b| = z

then we got two equation

ax + b = z

ax + b = -z

then solve x ......


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How many times can 448 go into 8
sveticcg [70]
It goes in 56 times. 448/8=56

7 0
3 years ago
Read 2 more answers
Use the figure and flowchart proof to answer the question:
KatRina [158]

Answer:

tSubstitution Property of Equality

Step-by-step explanation:

I took the test and that was the answer

4 0
3 years ago
You are ordering T-shirt with your school's mascot printed on them. Each T-shirt cost $4.75. The printer charges a setup fee of
masya89 [10]

Answer:

1. n(4.75+30+2.50)

2. 4.75n+30n+2.50n

Step-by-step explanation:

n is the number of shirts they buy. It says that each shirt costs $4.75, and for each shirt they add an extra $30 and $2.50 for the setup fee and to peint each shirt. The word each shows that you have to times. You have to times n by each number or to make it shorter put all three numbers in parenthesis put the n ouside of the parenthesis.

Hope that helps.

4 0
2 years ago
Read 2 more answers
15 decreased by twice a number x in algebriac expression
postnew [5]
2x - 15

15 is decreased that is the key word here which indicates subtraction.

twice a number with given variable x is 2x

subtraction always goes behind so 2x - 15
4 0
3 years ago
A tire manufacturer warranties its tires to last at least 20,000 miles orâ "you get a new set ofâ tires." In itsâ experience, a
Y_Kistochka [10]

Answer:

Probability that a set of tires wears out before 20,000 miles is 0.1151.

Step-by-step explanation:

We are given that a tire manufacturer warranties its tires to last at least 20,000 miles or "you get a new set of tires." In its past experience, a set of these tires last on average 26,000 miles with S.D. 5,000 miles. Assume that the wear is normally distributed.

<em>Let X = wearing of tires</em>

So, X ~ N(\mu=26,000,\sigma^{2}=5,000^{2})

Now, the z score probability distribution is given by;

         Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where, \mu = average lasting of tires = 26,000 miles

            \sigma = standard deviation = 5,000 miles

So, probability that a set of tires wears out before 20,000 miles is given by = P(X < 20,000 miles)

    P(X < 20,000) = P( \frac{X-\mu}{\sigma} < \frac{20,000-26,000}{5,000} ) = P(Z < -1.2) = 1 - P(Z \leq 1.2)

                                                                    = 1 - 0.88493 = 0.1151

Therefore, probability that a set of tires wears out before 20,000 miles is 0.1151.

4 0
3 years ago
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