1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
marin [14]
3 years ago
13

The distribution of the number of transactions performed at a bank each day is approximately normal with mean 478 transactions a

nd standard deviation 64 transactions. Which of the following is closest to the proportion of daily transactions greater than 350?
a. 0.023
b. 0.046
c. 0.954
d. 0.477
e. 0.977
Mathematics
1 answer:
jolli1 [7]3 years ago
6 0

Answer:

e. 0.977

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 478, \sigma = 64

Which of the following is closest to the proportion of daily transactions greater than 350?

This is 1 subtracted by the pvalue of Z when X = 350. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{350 - 478}{64}

Z = -2

Z = -2 has a pvalue of 0.023

1 - 0.023 = 0.977

So the correct answer is:

e. 0.977

You might be interested in
Pls help me
bekas [8.4K]

The composite function combines the palm tree and the seed functions

The composite function is t(d) = 60d + 20

<h3>How to determine the composite functions</h3>

The functions are given as:

Number of palm trees: t(s) = 3s + 20

Number of seeds: s(d) = 20d

The composite function that represents the number of palm trees Carlos can expect to grow over a certain number of days is represented as:

t(s(d))

This is calculated as:

t(s(d)) = 3s(d) + 20

Substitute s(d) = 20d

t(s(d)) = 3 * 20d + 20

Evaluate the product

t(s(d)) = 60d + 20

Rewrite as:

t(d) = 60d + 20

Hence, the composite function is t(d) = 60d + 20

Read more about composite functions at:

brainly.com/question/10687170

4 0
2 years ago
Find the linear approximation of the function g(x) = 3 root 1 + x at a = 0. g(x). Use it to approximate the numbers 3 root 0.95
Virty [35]

Answer:

L(x)=1+\dfrac{1}{3}x

\sqrt[3]{0.95} \approx 0.9833

\sqrt[3]{1.1} \approx 1.0333

Step-by-step explanation:

Given the function: g(x)=\sqrt[3]{1+x}

We are to determine the linear approximation of the function g(x) at a = 0.

Linear Approximating Polynomial,L(x)=f(a)+f'(a)(x-a)

a=0

g(0)=\sqrt[3]{1+0}=1

g'(x)=\frac{1}{3}(1+x)^{-2/3} \\g'(0)=\frac{1}{3}(1+0)^{-2/3}=\frac{1}{3}

Therefore:

L(x)=1+\frac{1}{3}(x-0)\\\\$The linear approximating polynomial of g(x) is:$\\\\L(x)=1+\dfrac{1}{3}x

(b)\sqrt[3]{0.95}= \sqrt[3]{1-0.05}

When x = - 0.05

L(-0.05)=1+\dfrac{1}{3}(-0.05)=0.9833

\sqrt[3]{0.95} \approx 0.9833

(c)

(b)\sqrt[3]{1.1}= \sqrt[3]{1+0.1}

When x = 0.1

L(1.1)=1+\dfrac{1}{3}(0.1)=1.0333

\sqrt[3]{1.1} \approx 1.0333

7 0
3 years ago
An engineer designed a valve that will regulate water pressure on an automobile engine. The engineer designed the valve such tha
natita [175]

Answer:

Step-by-step explanation:

Given that:

Population Mean = 7.1

sample size = 24

Sample mean = 7.3

Standard deviation = 1.0

Level of significance = 0.025

The null hypothesis:

H_o: \mu = 7.1

The alternative hypothesis:

H_a: \mu > 7.1

This test is right-tailed.

degree \ of \  freedom=  n - 1 \\ \\ degree \  of \  freedom  =  24 - 1 \\ \\ degree \ of \  freedom   = 23

Rejection region: at ∝ = 0.025 and df of 23, the critical value of the right-tailed test t_c = 2.069

The test statistics can be computed as:

t = \dfrac{ \hat X - \mu_o}{\dfrac{s}{\sqrt{n}}}

t = \dfrac{ 7.3-7.1}{\dfrac{1}{\sqrt{24}}}

t = \dfrac{0.2}{0.204}

t = 0.980

Decision rule:

Since the calculated value of t is lesser than, i.e t = 0.980 < t_c = 2.069, then we do not reject the null hypothesis.

Conclusion:

We conclude that there is insufficient evidence to claim that the population mean is greater than 7.1 at 0.025 level of significance.

6 0
3 years ago
Please answer this correctly I have to finish the sums today as soon as possible
padilas [110]

Answer:

All of them

Step-by-step explanation:

ツ

3 0
2 years ago
Answer please boys????
jasenka [17]
<ABC + <ABC = 180
3x- 9 + 7x - 1 = 180
10x - 10 = 180
10x = 190
x = 19

<ABC = 3x- 9 = 3(19) - 9 = 48
4 0
3 years ago
Read 2 more answers
Other questions:
  • System of equations.<br><br> 8th grade math<br><br> { y = 1/3 x + 2, x = 9
    10·1 answer
  • What is the answer to this 8-(-8)=
    8·2 answers
  • A box contains 6 blue pens and 10 red pens. What is the ratio of red pens to total pens as a fraction​
    14·2 answers
  • What is the value of x?
    10·2 answers
  • Cesar bought 2 bottles of juice that each hold 2 quarts and another bottle that holds 1 1/2 gallons of juice how many quarts of
    12·2 answers
  • A physicist examines 25 water samples for nitrate concentration. The mean nitrate concentration for the sample data is 0.165 cc/
    7·1 answer
  • Jamie King wants to buy a new car in 5 years. Jamie
    5·1 answer
  • Find the slope of the line through the points (-2, 4) and (6.-7)*
    11·1 answer
  • [Help Quick]. Fill in the table using this function rule
    12·2 answers
  • 5 5 I think of a number, treble it then add on 3, the result is equal to 6. Find the value of the original number I thought of.​
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!