Please, group your sets of numbers, using { } notation or at least semicolons ( ; ). Thanks.
Looking at what I think is your first set: { sqrt(4), sqrt(5), sqrt(16) }
Square each of these and then subst. the results into the Pythagorean Theorem:
{ 4, 5, 16 } Do 4 and 5 when added together result in 16? NO.
Therefore, { sqrt(4), sqrt(5), sqrt(16) } does not produce a right triangle.
Your turn. Pick out the next 3 numbers and test them using the Pyth. Thm.
Answer:
32
Step-by-step explanation:
From the given values
The possible logic could be
if x.y is given
then it is equal to![=\frac{(x+y)\times x}{y-3}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%28x%2By%29%5Ctimes%20x%7D%7By-3%7D)
For 1st example
3.4![=\frac{(3+4) \times 3}{4-3} =\frac{21}{1} =21](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%283%2B4%29%20%5Ctimes%203%7D%7B4-3%7D%20%3D%5Cfrac%7B21%7D%7B1%7D%20%3D21)
For 2nd example
2.5![=\frac{(2+5) \times 2}{5-3} =\frac{7 \times 2}{2} =7](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%282%2B5%29%20%5Ctimes%202%7D%7B5-3%7D%20%3D%5Cfrac%7B7%20%5Ctimes%202%7D%7B2%7D%20%3D7)
⇒4.4![=\frac{(4+4)\times 4}{4-3} =32](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%284%2B4%29%5Ctimes%204%7D%7B4-3%7D%20%3D32)
Answer:
![b)8](https://tex.z-dn.net/?f=b%298)
is the answer it's was helpful to you
Answer:
Mr. Sullivan <u>is</u> being fair because one tile has <u>an equal</u> probability of being selected over another tile.
Step-by-step explanation:
The process is fair because every tile has the same probability of being selected, and as the selection goes on, the selected students are removed.