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2 years ago

What is the value of x in the equation 5(3x + 4) = 23

Mathematics

1 answer:

abruzzese [7]2 years ago

4 0

5(3x+4)=23

15x+20=23

15x=23-20

15x=3

x=3/15

x=1/5=0.2

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How many hundred thousands equal 80,000 tens

kumpel [21]

The answer is 8 hoped that help always fell free to comment me if you have any more questions and always good luck

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2 years ago

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The midpoint of AB is M(7. – 7). If the coordinates of A are (8,-6), what are the

IRISSAK [1]

Answer: B = (6,-8)

Step-by-step explanation:

first the midpoint formula is $(\frac{x1+x2}{2},\frac{y1+y2}{2})$

then you take the x co-ordinate of A and substitute it into one of the x values in the first part of the formula:

$\frac{8+x}{2}=7$

then solve it like an equation:

$8+ x=14\\x=6$

then you take the y co-ordinate of A and substitute it into one of the y values in the second part of the midpoint formula:

$\frac{-6+y}{2} =-7$

then solve it like an equation:

$-6+y=-14\\y=-8$

∴ the answer is x=6, y= -8

which is expressed as a point, B(6,-8)

3 0

3 years ago

PLZ HURRY Solve for g.<br><br>g3 – 1 > 2

Phoenix [80]

$g3 - 1 > 2$

$g3 - 1 + 1 > 2 + 1$

$g3 > 3$

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2 years ago

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2 years ago

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Suppose that prices of recently sold homes in one neighborhood have a mean of $265,000 with a standard deviation of $9300. Using

Hatshy [7]

Answer:

Range = (237100, 292900)

Step-by-step explanation:

Using Chebyshevs Inequality:

$P(|X - \mu | \le k \sigma )\ge 1 -\dfrac{1}{k^2}= 0.889$

$1 -\dfrac{1}{k^2}= 0.889$

$\dfrac{1}{k^2}= 1- 0.889$

$\dfrac{1}{k^2}=0.111$

$k = \sqrt{\dfrac{1}{0.111}}$

$k \simeq 3$

Thus, 88.9% of the population is within 3 standard deviation of the mean with the Range = μ ± kσ

where;

μ = 265000

σ = 9300

Range = 265000 ± 3(9300)

Range = 265000 ± 27900

Range = (265000 - 27900, 265000 + 27900)

Range = (237100, 292900)

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2 years ago