Acceleration is a measure of the change in velocity of a moving object. :)
CoCl₂(s) → Co²⁺(aq) + 2Cl⁻(aq)
n(CoCl₂)=0.27 mol
n(Co²⁺)=n(CoCl₂)
n(Cl⁻)=2n(CoCl₂)
n=n(Co²⁺)+n(Cl⁻)=3n(CoCl₂)
n=3*0.27=0.81 mol
Answer:
Explanation:
2 HgCl₂ + C₂O₄²⁻ = 2 Cl⁻ + Hg₂Cl₂ + 2CO₂
1 )
Rate of reaction ![= k[HgCl_2]^m[C_2O_4^{-2}]^n](https://tex.z-dn.net/?f=%3D%20k%5BHgCl_2%5D%5Em%5BC_2O_4%5E%7B-2%7D%5D%5En)
[HgCl₂] [C₂O₄²⁻ ] Rate
1 . .124 .115 1.61 x 10⁻⁵
2 . .248 .115 3.23 x 10⁻⁵
3 . .124 .229 6.4 x 10⁻⁵
4 . .248 .229 1.28 x 10⁻⁴
comparing 1 and 3 , when concentration of HgCl₂ remains constant and concentration of C₂O₄²⁻ becomes twice , rate becomes 4 times so rate is proportional to square of concentration of C₂O₄²⁻ .
Hence n = 2
comparing 1 and 2 , when concentration of HgCl₂ becomes twice and concentration of C₂O₄²⁻ remains constant , rate becomes 2 times so rate is proportional to simply concentration of C₂O₄²⁻ .
Hence m = 1
Putting the data of 1 in the rate equation found
1.61 x 10⁻⁵ = k x .124 x .115²
k = 11.3 x 10⁻⁴ M⁻² s⁻¹
Answer:
im stuck on it too unfortunatley
Explanation:
Answer: N (the Nitrogen)
Explanation:
Reduction refers to a decrease in oxidation number/state due to the gaining of electrons. As such the species that is being reduced will show a decrease in oxidation state.
Based on the redox rules,
Zn(s) has oxidation number of 0 [<em>rule 1: the oxidation number of an element in its free (uncombined) state is zero</em>]
Zn²⁺ has oxidation number of +2 [<em>rule 2: The oxidation number of a monatomic (one-atom) ion is the same as the charge on the ion</em>]
Now, since Nitrogen is enbedded in a polyatomic ion in both cases, you have to do a bit a calculation to obtain the oxidation state.
For NO₃⁻ : N + (-2 × 3) = -1
N - 6 = -1
N = 5
<em>[Rule 3: The sum of all oxidation numbers in a polyatomic (many-atom) ion is equal to the charge on the ion; Rule 6: The oxidation state of hydrogen in a compound is usually +1]</em>
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For NH₄⁺ :
N + (4 x 1) = 1
N + 4 = 1
N = -3
[<em>Rule 3: The sum of all oxidation numbers in a polyatomic (many-atom) ion is equal to the charge on the ion; Rule 5: The oxidation number of oxygen in a compound is usually –2]</em>
Therefore, Zn moves from oxidation state of 0 to +2 (oxidation), while N moves from +5 to -3 (reduction).