Answer:
Step-by-step explanation:
Let “a” be the first term and ”r” the common ratio of the GP. Then,
f(n) = ar^(n - 1).
f(2) + f(3) = 6f(4). (given)
ar + ar^2 = 6ar^3, or
1 + r = 6r^2, or
6r^2 - r - 1 = 0,
(3r + 1)(2r - 1) = 0.
r = -1/3, or 1/2.
If the common ratio is positive and the second term is 8 we have,
ar = 8, or
a*1/2 = 8, or a = 16.
f(n) = 16*(1/2)^(n - 1) = 2^4*2^(1 - n), or
f(n) = 2^(5 - n).
The first six terms of the GP are : 16, 8, 4, 2, 1, 1/2,…
××××××××××
Checking : f(2) + f(3) = 6f(4), (given).
LHS = 8 + 4 = 12.
RHS = 6* 2 = 12.
LHS = RHS.
Are you in college bc what is that?
All sides of the squares are congruent. This means that when solving for area:
base x height
the base and height would be the same length, 6.25
Multiply
6.25 x 6.25 = 39.0625
39.0625 ft² should be your answer (if i'm thinking of significant digits correctly)
If it should be a whole number, then 39 ft² is your answer
hope this helps
f(x)=2x^2+0x-5
Find the vertex
0/4=0=x
Input x into the equation to find y or f(x)
0+0-5=f(x)
(0,-5) = Vertex
Now find a random x coordinate to input into the equation.
Let's do 4.
32+0-5=f(x)=27
It may not look like a parabola due to it being uneven.
Answer:
B
Step-by-step explanation:
The differences in the terms of f(x) are + 3, + 5, + 7
Since the differences are not constant the relationship is not linear
Note the differences in the differences are + 2, + 2,
The second differences are constant indicating a quadratic relationship
Note the relationship between x and f(x)
x = 1 → 1² = 1 ← require to add 5, that is 1 + 5 = 6 ← value of f(x)
x = 2 → 2² = 4 ← require to add 5, that is 4 + 5 = 9 ← value of f(x)
x = 3 → 3² = 9 ← require to add 5, that is 9 + 5 = 14 ← value of f(x)
x = 4 → 4² = 16 ← require to add 5, that is 16 + 5 = 21 ← value of f(x)
Thus f(x) = x² + 5 → B
