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3 years ago

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On a number line, show all points whose coordinates satisfy the following inequalities: PLEASE SHOW ON A NUMBER LINE PLEASE DO W

ELL |x-20| 1 |x+1.5| 2.5

1 answer:

lukranit [14]3 years ago

3 0

the answer is zfiekrk but you can

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Please help<br><br><br><br><br>solve the following:<br>6(x-6)-5(x-7)=x+6

Digiron [165]

Answer:

$no \: solution$

Step-by-step explanation:

1) Expand

$6x - 36 - 5x + 35 = x + 6$

2) Simplify 6x - 36 - 5x + 35 to x - 1.

$x - 1 = x + 6$

3) Cancle x on both sides.

$- 1 = 6$

4) Since −1 = 6 is false, there is no solution.

No Solution

Hence, this equation have no solution.

8 0

2 years ago

A circle with a radius of 5 is inscribed in a equilateral triangle. What is the area of the triangle's area minus the circle's a

Aleonysh [2.5K]

First off, the area of the circle would be 78.54

Now, you would do (area of the triangle)--- AT-78.54=answer

I don't know how to find the area of the triangle with just the circle's radius, so this is all I can do. I'm sorry!

4 0

3 years ago

pe ling needs 2 yards of fabric for a craft project. she has 3 feet already.how many niches of fabric does she still need?

spin [16.1K]

2yards= 72 inches
72 inches= 6 feet

so now that you know that, you know that she needs 6 feet and already has 3 feet. so she just needs 3 feet more. but they are asking for the answer to be in inches.

3 feet= 36 inches
your answer in 36 inches

5 0

3 years ago

Suppose that a college determines the following distribution for X = number of courses taken by a full-time student this semeste

lidiya [134]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74$ In order to find the variance we need to calculate first the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36$ And the variance is given by:

$Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924$

And the deviation would be:

$Sd(X) =\sqrt{0.8924} =0.9447$

Step-by-step explanation:

Previous concepts

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

Solution to the problem

For this case we have the following distribution given:

X 3 4 5 6

P(X) 0.07 0.4 0.25 0.28

We can calculate the mean with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74$

In order to find the variance we need to calculate first the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36$

And the variance is given by:

$Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924$

And the deviation would be:

$Sd(X) =\sqrt{0.8924} =0.9447$

3 0

3 years ago

Please help me answer this question

Oliga [24]

Answer:

B

Step-by-step explanation:

7 0

3 years ago