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sasho [114]
3 years ago
13

Evaluate (ab)^2 for a=4 and b=3. A. 81B. 144C. 24D. 36

Mathematics
1 answer:
worty [1.4K]3 years ago
8 0
Substitute the number for the appropriate variables and solve
(ab)^2
(4×3)^2
(12)^2
12×12
144
Your answer is B.144
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Evaluate.<br> (-4)=<br> (-7) = 0<br> Please help ASAP!!
denis-greek [22]
  • Answer:

<em>(-4)³ = (-4)(-4)(-4) = 16(-4) = - 64</em>

<em>(-7)² = (-7)(-7) = 49</em>

<em>(-)×(-) = +</em>

<em>(-)×(+) = -</em>

4 0
3 years ago
What is 0.433 rounded to the nearest tenths
Fynjy0 [20]
0.433 is already rounded to the hundredths so to round it to the nearest tenths, remove the last number.

Your answer is 0.43
6 0
3 years ago
Read 2 more answers
Do most students walk, bike, or bus to school?
bonufazy [111]

Answer:

Most students ride the bus since the pie chart section is biggest at the bus section.

23 people walking / 100 people is 23% and 23% of 100 is 23 people.

Step-by-step explanation:

5 0
3 years ago
A two digit number when read from left to right to right consiststs of consecutive integers. the nmber is six more than for time
Solnce55 [7]

I suppose you want to know such number. Since we have a two digit number consisting of two consecutive integers, the only possible numbers are:

12,23,34,45,56,67,78,89

Since we sorted all the cases out, we simply have to check which one satisfies the requirement. For each number, we'll write four times the the sum of its digits, and add 6, hoping to get the original number.

\text{Number: } 12,\ \ 4\times \text{sum of digits: } 12\ \ \text{plus six: } 18\neq 12

\text{Number: } 23,\ \ 4\times \text{sum of digits: } 24\ \ \text{plus six: } 30\neq 23

\text{Number: } 34,\ \ 4\times \text{sum of digits: } 28\ \ \text{plus six: } 34

So, the answer is 34.

3 0
3 years ago
Mr. Kohl has a breaker containing n milliliters of solution to distribute to the students in his chemistry class. If he gives ea
77julia77 [94]

Answer:

There were 26 students in his class and the teacher had 83 ml of the solution.

Step-by-step explanation:

Mr. Kohl has a "x" amount of solution, if he divides it by the number of students "n" he'll give each student 3 milliliters  and have a left over of 5 milliliters. If the amount of solution Mr. Kohl had was "x + 21" then he'd be able to give each student 4 milliliters of the solution. From these informations we have:

x = 3*n + 5

(x + 21)/n = 4

x + 21 = 4*n

x = 4*n - 21

Now that we have two equations and two variables we can solve the system of equations, as seen bellow:

3*n + 5 = 4*n - 21

3*n - 4*n = -21 - 5

-n = -26

n = 26

x = 4*26 - 21 = 83 ml

There were 26 students in his class and the teacher had 83 ml of the solution.

3 0
2 years ago
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