Answer:
There are 21 flares there
Step-by-step explanation:
Firstly, we need to know how large the circle is
To calculate how large the circle is , we need to know what the circumference of the circle is
Mathematically, the circumference of a circle = pi * D
where D is the diameter of the circle and pi = 22/7
Thus, the circumference of the circle = 22/7 * 10.5m = 33m
Now, to know the number of flares, we divide the circumference of the circle by the the distance between the flares
That would be 33/1.57 = approximately 21
Answer:
Step-by-step explanation:
First, as you can see, the sequence is alternating its sign everytime, so you can deduce this term:
The sequence start from 3, and the following terms are the product between 3 and . Take a look:
For n=1
For n=2
And so on...
Let's verify the formula including all terms:
Since the sequence start from 3, we must change the 3 for -3. Because is always negative for the first term:
For n=1
For n=2
For n=3
For n=4
So, one possible sequence is:
And the serie would be given by:
(a) r = the weight of Rajesh's package and m = the weight of Mohib's package:
r = 2m + 3
r + m = 15
(b) The easiest way to solve this equation would be to use substitution. The first equation says that r is equal to "2m + 3", so we can plug 2m + 3 in for the r in the second equation, and then solve for m:
Now that we have m, we can plug it into one of the equations to find r:
So, the weight of Rajesh's package is 11 pounds, and the weight of Mohib's package is 4 pounds. This makes sense because both of these add up to 15 and Rajesh's package is three more than two times the weight of Mohib's package, as described in the question.
(c) Mohib's graph is the correct graph because it intersects at the correct point (4 on the Mohib axis and 11 on the Rajesh axis). The other graph shows the intersection of the two lines at the wrong point, giving the wrong weights of the two packages.