Question

An angle, θ, is in standard position. The terminal side of the angle passes through the point (4, 5).

Answer 1

Answer:

cos Θ = $\frac{4}{\sqrt{41} }$

Step-by-step explanation:

Given the angle passes through (4, 5 ) then the right triangle with sides 4 and 5 has hypotenuse h given by

h² = 4² + 5² = 16 + 25 = 41 ( take the square root of both sides )

h = $\sqrt{41}$

In relation to Θ, 4 is adjacent and 5 is opposite, thus

cos Θ = $\frac{adjacent}{hypotenuse}$ = $\frac{4}{\sqrt{41} }$