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3 years ago

In similar triangles, corresponding angles are congruent. True False

Mathematics

2 answers:

Kisachek [45]3 years ago

6 0

True because they are the same shape but not necessarily the same size.

Mamont248 [21]3 years ago

5 0

I got true

i hope this helps

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PLEASE ANSWER ASAP PLEAS

garik1379 [7]

Answer:

d only.

Step-by-step explanation:

lol i know ur map testing, i had the same question yesterday

5 0

2 years ago

A certain candle is designed to last nine hours. However, depending on the wind, air bubbles in the wax, the quality of the wax,

Ierofanga [76]

Answer:

Step-by-step explanation:

a) P(X > 6) = (9.5-6)/(9.5-5.5) = 3.5/4 = 0.875

b) P(X < 7) = (7-5.5)/(9.5-5.5) = 1.5/4 = 0.375

c) E(X) = (9.5+5.5)/2 = 7.5

Standard deviation = (9.5-5.5)/sqrt(12) =4/3.46 = 1.154

P= 1.156*2/(9.5-5.5) = 2.308/4 = 0.577

d) P(X > t) = 0.25

(9.5-t) /(9.5-5.5) = 0.3

9.5-t = 1.2

t = 9.5-1.2 = 8.3

5 0

2 years ago

The table gives information about the heights, in cm, of some children.

marusya05 [52]

The mean height would be 155

6 0

2 years ago

Determine if the points A(1,-3), B(4,4), and C(5,8) are collinear.

myrzilka [38]

Answer:

Step-by-step explanation:

since;

(4--3)/(4-1)≠(8-4)/(5-4)

4 0

2 years ago

Use the given information to find the minimum sample size required to estimate an unknown population mean μ.

larisa86 [58]

Answer:

The number of business students that must be randomly selected to estimate the mean monthly earnings of business students at one college is 64.

Step-by-step explanation:

The (1 - α) % confidence interval for population mean is:

$CI=\bar x\pm z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}$

The margin of error for this interval is:

$MOE= z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}$

The information provided is:

σ = $569

MOE = $140

Confidence level = 95%

α = 5%

Compute the critical value of z for α = 5% as follows:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

*Use a z-table.

Compute the sample size required as follows:

$MOE= z_{\alpha/2}\ \frac{\sigma}{\sqrt{n}}$

$n=[\frac{z_{\alpha/2}\times \sigma}{MOE}]^{2}$

$=[\frac{1.96\times 569}{140}]^{2}\\\\=63.457156\\\\\approx 64$

Thus, the number of business students that must be randomly selected to estimate the mean monthly earnings of business students at one college is 64.

4 0

3 years ago