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Sloan [31]
3 years ago
10

HALP Solve: |y + 8| ≥ 3

Mathematics
2 answers:
NemiM [27]3 years ago
8 0
The answers gonna be (-17=y)

creativ13 [48]3 years ago
8 0
For
|x|≥y, solve for x such that
x≤-y or x≥y


|y+8|≥3
solve for
y+8≤-3 or y+8≥3
minus 8 from both sides
y≤-11 or y≥-5


the solution set is y≤-11 or y≥-5
basically, all real numbers except z, such that -11<z<-5


the solution set is y≤-11 or y≥-5

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-2(x+1)+6x&lt;-14<br>I need help​
jeka57 [31]

Answer:

x<-3

Step-by-step explanation:

-2(x+1)+6x<-14

Distribute

-2x-2 + 6x < -14

Combine like terms

4x -2 < -14

Add 2 to each side

4x-2+2 < -14+2

4x < -12

Divide by 4

4x/4 < -12/4

x<-3

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Answer:

Step-by-step explanation:

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3 years ago
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zmey [24]

Answer:

H: (2, 14)

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OleMash [197]

4) -0.3 = -1/3 < -1/7 since the bigger a negative number is the less positive it is. 1/8 is positive so it is clear that it should be placed last. & thus do all options this way.

5) B

Area of a triangle = ½ bh.

where b = base &

h = height.

Area of outer shape = (½ x 16 x 12) in^2.

= 96 in^2.

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= 6 in^2.

Area of shaded region = (96 – 6) in^2.

= 90 in^2.

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lina2011 [118]
190
- 15
------
175 pounds
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4 years ago
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