A) Demand function
price (x) demand (D(x))
4 540
3.50 810
D - 540 810 - 540
----------- = -----------------
x - 4 3.50 - 4
D - 540
----------- = - 540
x - 4
D - 540 = - 540(x - 4)
D = -540x + 2160 + 540
D = 2700 - 540x
D(x) = 2700 - 540x
Revenue function, R(x)
R(x) = price * demand = x * D(x)
R(x) = x* (2700 - 540x) = 2700x - 540x^2
b) Profit, P(x)
profit = revenue - cost
P(x) = R(x) - 30
P(x) = [2700x - 540x^2] - 30
P(x) = 2700x - 540x^2 - 30
Largest possible profit => vertex of the parabola
vertex of 2700x - 540x^2 - 30
When you calculate the vertex you find x = 5 /2
=> P(x) = 3345
Answer: you should charge a log-on fee of $2.5 to have the largest profit, which is $3345.
I think u add not sure though
Answer:
-1/3
Step-by-step explanation:
Taking two points on the graph (I took (0,9) and (6,7)
Slope=(y2-y1)/(x2-x1)
(7-9)/(6-0)=-2/6
=-1/3
Answer:
0.01p + 0.05n > 40
0.01p + 0.05n < 20
Step-by-step explanation:
it has to be MORE (greater) than 40
it has to be LESS than 20 coins
hope this helps
not sure if you have to write the second equation, so sorry if it's wrong. :)
