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Valentin [98]
2 years ago
9

The cost C, in dollars, to have medical records transcribed is a function of time, t in hours. A physician's group spends C(t) =

0.04t3 – 0.1t2 + 5.5t dollars to transcribe the physician's. Notes to an electronic document each month. What is the instantaneous rate of change when the transcriptionist has spent 100 hours transcribing records? A) $118.50 B)$395.50 C)$1,185.50 D)$1,195.50
Mathematics
1 answer:
Contact [7]2 years ago
3 0

Answer:

B. $39550

Step-by-step explanation:

The expression for the function is not well-formatted, find the correct format in the solution bellow

Step one:

given data

We are told that the function of the cost is

C(t) = 0.04t^3- 0.1t^2 + 5.5t

instantaneous rate c(t) is the value obtained when we plug in 100 for t in the function above

substituting we have

C(t) = 0.04(100)^3- 0.1(100)^2 + 5.5(100)\\\\\C(t) = 0.04*1000000- 0.1*10000 + 5.5*100\\\\C(t) = 40000-1000+550\\\\C(t) = 39550

$39550

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Two brands of AAA batteries are tested in order to compare their voltage. The data summary can be found below.
garik1379 [7]

Answer:

The 95% confidence interval would be given by 0.281 \leq \mu_1 -\mu_2 \leq 0.529  

Step-by-step explanation:

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

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\sigma_2 =0.1 population standard deviation for sample 2

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Solution to the problem

The confidence interval for the difference of means is given by the following formula:  

(\bar X_1 -\bar X_2) \pm z_{\alpha/2}\sqrt{\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2}} (1)  

The point of estimate for \mu_1 -\mu_2 is just given by:

\bar X_1 -\bar X_2 =9.2-8.8=0.4

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that t_{\alpha/2}=1.96  

Now we have everything in order to replace into formula (1):  

0.4-1.96\sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}=0.281  

0.4+1.96\sqrt{\frac{6^2}{36}+\frac{7^}{49}}=0.519  

So on this case the 95% confidence interval would be given by 0.281 \leq \mu_1 -\mu_2 \leq 0.529  

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3 years ago
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2 years ago
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6) What are ED and FD?
kolezko [41]

Answer:

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Step-by-step explanation:

See the attached diagram.

The perpendicular distance between the three parallel lines are same i.e. AB = BC = 8

Therefore, the parallel lines will divide any transverse line ( say FD ) in 1 : 1 ratio i.e. will divide equally.

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