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Feliz [49]
3 years ago
8

Help please! Will give brainliest

Mathematics
2 answers:
arsen [322]3 years ago
7 0
It is c 135m2 thts the area of the kitee
motikmotik3 years ago
4 0

Option c is correct. Use special right triangles and you will findout why. Hint:Use the 45-45-90 special right triangle's properties.

You might be interested in
Would x= 8 be a solution to equation × +10=24?​
ella [17]

Answer:

No, 8+10=18 but, 14+10=24 which means x=14

Step-by-step explanation:

6 0
3 years ago
Use separation of variables to solve dy dx − tan x = y2 tan x with y(0) = √3. Find the value of c in radians, not degrees
a_sh-v [17]

Answer:

y(x)=tan(-log(cos(x))+\frac{\pi }{3} )

Step-by-step explanation:

Rewrite the equation as:

\frac{dy(x)}{dx}-tan(x)=y(x)^{2} *tan(x)

Isolating \frac{dy}{dx}

\frac{dy}{dx} =tan(x)+tan(x)*y^{2}

Factor:

\frac{dy}{dx} =tan(x)*(1+y^{2} )

Dividing both sides by (1+y^{2} ) and multiplying them by dx

\frac{dy}{1+y^{2} } =tan(x)dx

Integrate both sides:

\int\ \frac{dy}{1+y^{2} } = \int\ tan(x)  dx

Evaluate the integrals:

arctan(y)=-log(cos(x))+C_1

Solving for y:

y(x)=tan(-log(cos(x))+C_1)

Evaluating the initial condition:

y(0)=\sqrt{3} =tan(-log(cos(0))+C_1)=tan(-log(1)+C_1)=tan(0+C_1)

\sqrt{3} =tan(C_1)\\arctan(\sqrt{3} )=C_1\\60=C_1

Converting 60 degrees to radians:

60degrees*\frac{\pi }{180degrees} =\frac{\pi }{3}

Replacing C_1 in the diferential equation solution:

y(x)=tan(-log(cos(x))+\frac{\pi }{3} )

3 0
3 years ago
What is reasonable estimate for 467023
Galina-37 [17]
470000 is the most reasonable
6 0
3 years ago
Read 2 more answers
Write the equation of the parabola that has the vertex at point (2,7) and passes through
Anton [14]

Answer:

f(x) =  \frac{4}{3} (x - 2) ^{2}  + 7

Step-by-step explanation:

the answer is :- .

f(x) =  \frac{4}{3} (x - 2) ^{2}  + 7

6 0
2 years ago
79% of 67 miles is what?
KIM [24]
To do it without a calculator:

10% of 67 is 6.7
6.7 x 8 is 53.6 (80%)
1% of 67 is .67
<span>53.6 - .67 is 52.93 (79%)</span>
3 0
4 years ago
Read 2 more answers
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