If each pack of trail mixes is targeted to weigh 9.25 oz and must be within 0.23 oz of the target in order to be accepted, then rejected masses x, are those which weighs less than 9.02 oz or greater than 9.48 oz.
Answer:
C
Step-by-step explanation:
Given
Divide each term on the numerator by 4x
= 
+ 
+ 
= 
+ 2 +
54, 36, 24 are the 1st 3 element of a geometric progression with 2/3 as a common ratio: PROOF:
the 1st term is 54, (a₁= 54) the 2nd term a₂ = 24, then
(a₂ = a₁.r) or 36 = 54.r → r= 36/54 = 2/3. Same logique for the 3rd term.
So 2/3 is common ratio. We know that :U(n) = a.(r)ⁿ⁻¹. Then if a =54 and r = x (given by the problem), then f(x) = 54.xⁿ⁻¹
n, being the rank of any element of this geometric progression
Answer:
730, 735, 740
Step-by-step explanation:
Let the three consecutive multiples of 5 be, x, x+5 and x+10
Given,
x + x+5 + x+10 = 2205
3x + 15 = 2205
Subtract 15 from both sides,
3x = 2205 - 15
3x = 2190
Divide both sides by 3,
x = 2190/3 = 730
So, x= 730
x+5 = 735
x+10 = 740
