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grigory [225]
3 years ago
9

an equation in slope-intersept form the lines that passes thought (-8,1) and is perpindicular to the y=2x-17.

Mathematics
1 answer:
juin [17]3 years ago
5 0

Answer:

y = (-1/2)x -3

Step-by-step explanation:

We are given

y = 2x-17

which is in slope-intercept form: y = mx +b

Where m is the slope. so, m= 2

But this is perpendicular, When a line is perpendicular then the slope become -1/m so in our case the slope m will be = -1/2

Using the point(-8,1) we can find the b i.e the y intercept

We have x = -8, y =1 and m=-1/2

y = mx + b

1 = (-1/2)(-8) + b

1 = 4 + b

=> b = 1-4

b = -3

The equation of slope intercept form will be

y = mx + b

Putting value of m= -1/2 and b = -3

y = (-1/2)x -3

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Find AM, if AM = 6y-4 and MC = 2y+12.
aleksley [76]

Answer: 20

Step-by-step explanation:

Since Line l is a segment bisector, we know that AM and MC are equal to each other.

6y-4=2y+12        [subtract both sides by 2y]

4y-4=12              [add both sides by 4]

4y=16                 [divide both sides by 4]

y=4

Now that we have y, we plug that into AM.

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24-4                   [subtract]

20

Now, we know that AM is 20.

6 0
3 years ago
In 1928, when the high jump was first introduced as a women's sport at the Olympic Games, the winning jump for women was 70.0 in
sveta [45]

Answer: year 2194



Explanation:



1) Model the jump of the women:


i) initial jump = 70.0 in


ii) increase rate = 0.48% per year


iii) equation: h = 70.0(1 +0.0048)ⁿ


2) Model the jump of the men:


i) initial jump 86.5 inches.


ii) increase rate, 0.4%.


iii) equation: h = 86.5 (1 + 0.004)ⁿ


3) Equal the two equations (h = h) to find when the jumps will be equal:


i) 70.0(1 +0.0048)ⁿ = 86.5 (1 + 0.004)ⁿ


ii) 70.0(1.0048)ⁿ = 86.5 (1.004)ⁿ


ii) [1.0048ⁿ / 1.004ⁿ] = 86.5/70.0


iii) [1.0048/ 1.0040]ⁿ = 86.5/70.0


iv) n log (1.0048 / 1.0040) = log ( 86.5/70)


v) n = log (86.5/70) / log (1.0048/1.0040) ≈ 266


3) year = 1928 + 266 = 2194


That is in the year 2194

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Answer:

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Step-by-step explanation:

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