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mafiozo [28]
4 years ago
13

CO2 + H2O -------> H2CO3 balance and classify this equation

Chemistry
2 answers:
borishaifa [10]4 years ago
6 0
CO2 + H2O = H2CO3
<span>
Your equation is already balanced, and the reaction type is: </span><em><u>synthesis.</u></em>
OLga [1]4 years ago
4 0
CO2 + H2O = H2CO3
<span>
Your equation is already balanced, and the reaction type is: </span><span>synthesis.</span>
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How many protons and electrons are in Hg+
Gala2k [10]

Answer:

There are 80 protons and 80 electrons in Hg+ (Mercury)

Explanation:

Name Mercury

Symbol Hg

Atomic Number 80

Atomic Mass 200.59 atomic mass units

Number of Protons 80

Number of Neutrons 121

Number of Electrons 80

Melting Point -38.87° C

Boiling Point 356.58° C

Density 13.456 grams per cubic centimeter

Normal Phase Liquid

Family Transitions Metals

Period Number 6

8 0
3 years ago
If a person weighs 87lbs and has to be given a drug with a dosage of 50 milligrams per kilogram body weight, how many grams of t
Katarina [22]

Answer:

1 957,5

Explanation:

87libs=39.5kg that equals 50=1.957.5

7 0
3 years ago
What chemical property is most commonly used to classify igneous rocks?
iren2701 [21]

<span>Actually Igneous rocks are classified either based on grain size or based on mineralogy. However grain size is clearly not a chemical property. So we can say that they are classified chemically based on mineralogy or the abundance of quartz or silica present.</span>

7 0
3 years ago
Which of these is a balanced chemical equation?
Alex777 [14]
I believe its G because it has the same amount of particles. (I haven't had much background)
3 0
4 years ago
Read 2 more answers
Lead melts at 328 ℃. How much heat is required when 23.0 g of solid lead at 297 K condenses to a liquid at 702 K?
son4ous [18]

Heat = 1.74 kJ

<h3>Further explanation</h3>

Given

melts at 328 ℃ + 273 = 601 K

mass = 23 g = 0.023 kg

initial temperature = 297 K

Final tmperature = 702 K

Required

Heat

Solution

1. raise the temperature(297 to 601 K)

c of lead = 0.130 kJ/kg K

Q = 0.023 x 0.13 x (601-297)

Q = 0.909 kJ

2. phase change(solid to liquid)

Q = m.Lf (melting/freezing)

Q = 0.023 x 23 kj/kg = 0.529 kJ

3. raise the temperature(601 to 702 K)

Q = 0.023 x 0.13 x (702-601)

Q = 0.302 kJ

Total heat = 1.74 kJ

7 0
3 years ago
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