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Dmitrij [34]
3 years ago
9

If you collect 1.75 L of hydrogen gas during a lab experiment when the room temperature is 23oC and the barometric pressure is 1

05 kPa how many moles of hydrogen will you have
Chemistry
1 answer:
ziro4ka [17]3 years ago
8 0

Answer:

n=0.0747mol

Explanation:

Hello,

In this case, since we can consider hydrogen gas as an ideal gas, we check the volume-pressure-temperature-mole relationship by using the ideal gas equation:

PV=nRT

Whereas we are asked to compute the moles given the temperature in Kelvins, thr pressure in atm and volume in L as shown below:

n=\frac{105kPa*\frac{0.009869atm}{1kPa}*1.75L}{0.082\frac{atm*L}{mol*K}*(23+273.15)K} \\\\n=0.0747mol

Best regards.

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If a solution containing 117.63 g of silver chlorate is allowed to react completely with a solution containing 10.23 g of lithiu
GuDViN [60]

Answer:

18.8 g

Explanation:

The equation of the reaction is;

AgClO3(aq) + LiBr(aq)------>LiClO3(aq) + AgBr(s)

Number of moles of AgClO3 = 117.63 g/191.32 g/mol = 0.6 moles

Number of moles of LiBr = 10.23 g/86.845 g/mol  = 0.1 moles

Since the molar ratio is 1:1, LiBr is the limiting reactant

Molar mass of solid AgBr = 187.77 g/mol

Mass of precipitate formed = 0.1 moles * 187.77 g/mol

Mass of precipitate formed = 18.8 g

8 0
3 years ago
What is the difference between being imaginative in doing science and doing psuedoscience?
Dovator [93]
Being imaginative in doing science is using your knowledge and creativity to make innovative ideas, while psuedoscience is using sources that are not true and do not use actual science. Example being ads that say "Wow you will not believe what how this oil cured cancer!".
4 0
3 years ago
Question 2 (2 points)
poizon [28]

Answer:

m_w=439.2g

Explanation:

Hello!

In this case, since the by-mass percent of a solution is a measure of the mass of the solute over the mass of the solution:

\%m/m=\frac{m_{solute}}{m_{solution}} *100\%

As we know the mass of the solution and the by-mass percent, we can compute the mass of glucose in the 480 g of solution:

m_{solute}=\frac{\%m/m*m_{solution}}{100\%}

Thus, by plugging in the data, we obtain:

m_{solute}=\frac{8.5\%*480g}{100\%}=40.8g

Finally, since the solution is made up of glucose and water, we compute the mass of water as follows:

m_w=m_{sol}-m_{solute}=480g-40.8g\\\\m_w=439.2g

Best regards!

7 0
3 years ago
Find the mass of 3.27 x 10^23 molecules of H2SO4. Use 3 significant digits<br> and put the units.
marta [7]

Answer:

Approximately 53.3\; \rm g.

Explanation:

Lookup Avogadro's Number: N_{\rm A} = 6.02\times 10^{23}\; \rm mol^{-1} (three significant figures.)

Lookup the relative atomic mass of \rm H, \rm S, and \rm O on a modern periodic table:

  • \rm H: 1.008.
  • \rm S: 32.06.
  • \rm O: 15.999.

(For example, the relative atomic mass of \rm H is 1.008 means that the mass of one mole of \rm H\! atoms would be approximately 1.008\! grams on average.)

The question counted the number of \rm H_2SO_4 molecules without using any unit. Avogadro's Number N_{\rm A} helps convert the unit of that count to moles.

Each mole of \rm H_2SO_4 molecules includes exactly (1\; {\rm mol} \times N_\text{A}) \approx 6.02\times 10^{23} of these \rm H_2SO_4 \! molecules.

3.27 \times 10^{23} \rm H_2SO_4 molecules would correspond to \displaystyle n = \frac{N}{N_{\rm A}} \approx \frac{3.27 \times 10^{23}}{6.02 \times 10^{23}\; \rm mol^{-1}} \approx 0.541389\; \rm mol of such molecules.

(Keep more significant figures than required during intermediary steps.)

The formula mass of \rm H_2SO_4 gives the mass of each mole of \rm H_2SO_4\! molecules. The value of the formula mass could be calculated using the relative atomic mass of each element:

\begin{aligned}& M({\rm H_2SO_4}) \\ &= (2 \times 1.008 + 32.06 + 4 \times 15.999)\; \rm g \cdot mol^{-1} \\ &= 98.702\; \rm g \cdot mol^{-1}\end{aligned}.

Calculate the mass of approximately 0.541389\; \rm mol of \rm H_2SO_4:

\begin{aligned}m &= n \cdot M \\ &\approx 0.541389\; \rm mol \times 98.702\; \rm g \cdot mol^{-1}\\ &\approx 53.3\; \rm g\end{aligned}.

(Rounded to three significant figures.)

6 0
3 years ago
In which type of condition is a conditions is a landslide most likely to occur
masha68 [24]

Answer:

<u>B. In a wet, hilly area</u>

Explanation:

We know that for a landslide to happen, there has to be a down hill slope so it can fall.

This eliminates answers C, D and E.

So we are left with A and B

Now we can look at this in a real life scenario. If you have ever walking on wet ground, you will know that is weaker than dry ground. Knowing this, we know the answer will have to be answer B.

6 0
3 years ago
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