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kakasveta [241]

3 years ago

11

If the initial concentration of N2O5 was 0.500 M and the concentration of N2O5 was 0.450 M after 0.100 s, what is the average ra

te of NO2 formation during the first 100 milliseconds

1 answer:

pentagon [3]3 years ago

7 0

Answer:

The appropriate solution is "1 M/s".

Explanation:

The equation is:

$2N_2O_5 \rightarrow4NO_2+O_2$

or,

$\frac{1}{2}(-\frac{\Delta(N_2O_5)}{dt} ) =\frac{1}{4}\frac{\Delta (NO_2)}{dt}$

then,

The rate of $NO_2$ formation:

= $\frac{\Delta NO_2}{dt}$

= $\frac{4}{2} (-\frac{\Delta(N_2O_5)}{dt})$

= $2(-\frac{\Delta (N_2O_5)}{dt} )$

= $2(-\frac{(0.45-0.5)}{0.1} )$

= $1 \ M/s$

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If the pka of hcho2 is 3.74 and the ph of an hcho2/nacho2 solution is 3.89, it means that

Andrei [34K]

Hi, the question has some missing part. The complete question should be " If the $pK_{a}$ of $HCHO_{2}$ is 3.74 and the pH of an $HCHO_{2}/NaCHO_{2}$ solution is 3.89, it means that -

(a) $[HCHO_{2}]=[NaCHO_{2}]$

(b) $[HCHO_{2}]> [NaCHO_{2}]$

(c) $[HCHO_{2}]< [NaCHO_{2}]$

Which of the options are true?"

Answer: Option (c) is true.

Explanation:

$HCHO_{2}/NaCHO_{2}$ is an weak acid-conjugate base buffer. Hence, in accordance with Henderson-Hasselbalch equation-

$pH=pK_{a}(HCHO_{2})+log(\frac{[CHO_{2}^{-}]}{[HCHO_{2}]})$

Here, pH = 3.89, $pK_{a}$ of $HCHO_{2}$ = 3.74

So, $3.89=3.74+log(\frac{[CHO_{2}^{-}]}{[HCHO_{2}]})$

or, $\frac{[CHO_{2}^{-}]}{[HCHO_{2}]}$ = 1.41 (>1)

So, $[CHO_{2}^{-}]> [HCHO_{2}]$

or, $[NaCHO_{2}]> [HCHO_{2}]$

Hence, option (c) is correct.

6 0

4 years ago

What definition BEST describes a watershed?

stellarik [79]

Answer:

An area or ridge of land that separates waters flowing to different rivers, basins, or seas.

Explanation:

7 0

3 years ago

Give the number and type of hybrid orbital that forms when each set of atomic orbitals mixes:

evablogger [386]

<u>Two hybrid </u>orbitals of <u>sp </u>type forms when each set of atomic orbitals mixes one p and one s

<h3>What is orbital hybridization?</h3>

In the context of valence bond theory, orbital hybridization (or hybridisation) refers to the idea of combining atomic orbitals to create new hybrid orbitals (with energies, forms, etc., distinct from the component atomic orbitals) suited for the pairing of electrons to form chemical bonds.

For instance, the valence-shell s orbital joins with three valence-shell p orbitals to generate four equivalent sp3 mixes that are arranged in a tetrahedral configuration around the carbon atom to connect to four distinct atoms.

Hybrid orbitals are symmetrically arranged in space and are helpful in the explanation of molecular geometry and atomic bonding characteristics. Usually, atomic orbitals with similar energies are combined to form hybrid orbitals.

Learn more about Hybridization

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8 0

2 years ago

Which equation represents a change that results in an increase in disorder?(1 ) I2(s)=>I2(g)

ankoles [38]

Answer : The correct option is, (1) $I_2(s)\rightarrow I_2(g)$

Explanation :

Entropy : It measures the disorderedness or randomness of the molecule.

That means higher the disorderedness, higher will be the entropy.

As we are going from solid state to liquid state, liquid state to gaseous state, the disorderedness increases due to the less inter-molecular interaction between the molecules.

And, as we are going from gaseous state to liquid state, liquid state to solid state, the disorderedness decreases due to the more inter-molecular interaction between the molecules.

(1) $I_2(s)\rightarrow I_2(g)$

In this reaction, the disorderedness increases because the state changes from solid to liquid.

(2) $CO_2(g)\rightarrow CO_2(s)$

In this reaction, the disorderedness decreases because the state changes from gaseous to solid.

(3) $2Na(s)+Cl_2(g)\rightarrow 2NaCl(s)$

In this reaction, the disorderedness decreases because the state changes from gaseous to solid.

(4) $2H_2(g)+O_2(g)\rightarrow 2H_2O(l)$

In this reaction, the disorderedness decreases because the state changes from gaseous to liquid.

Hence, the correct option is, (1) $I_2(s)\rightarrow I_2(g)$

8 0

3 years ago

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Which statement is correct about charges?

V125BC [204]

Answer:

A.Opposite charges repel

8 0

3 years ago

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