(a) In this section, give your answers to three decimal places.
(i)
Calculate the mass of carbon present in 0.352 g of CO
2
.
Use this value to calculate the amount, in moles, of carbon atoms present in 0.240 g
of
A
.
(ii)
Calculate the mass of hydrogen present in 0.144 g of H
2
O.
Use this value to calculate the amount, in moles, of hydrogen atoms present in 0.240 g
of
A
.
(iii)
Use your answers to calculate the mass of oxygen present in 0.240 g of
A
Use this value to calculate the amount, in moles, of oxygen atoms present in 0.240 g
of
A
(b)
Use your answers to
(a)
to calculate the empirical formula of
A
thank you
hope it helpsss
The number of hydrogen atoms is twice the number of oxygen atoms in ribose.
<h3>What is Ribose?</h3>
This is a sugar and a component of the ribonucleotides from which RNA is built. It has the formula C₅H₁₀O₅.
Ribose is a carbohydrate with the formula C₅H₁₀O₅. This molecule is a pentose monosaccharide which has a linear form 
. The hydroxyl groups lie on the same side in the form of Fischer Projections.
The number of hydrogen atoms is double the number of oxygen atoms. The ribose sugar is found in the RNA.
It is the genetic material which is found in some organisms that carry information from one generation to another.
Read more about Ribose here:
brainly.com/question/923091
#SPJ1
<span>Density
is a value for mass, such as kg, divided by a value for volume, such as m3.
Density is a physical property of a substance that represents the mass of that
substance per unit volume. We calculate as follows:
Density = mass of gasoline/ volume of gasoline = (1</span>46.770 g -110.525 g ) / <span>50 ml = 0.7249 g/mL</span>
Answer: A and D
Explanation: isotopes must have same atomic number but different mass number due to the difference in their Neutron number
Answer:
1.7 mL
Explanation:
<em>A chemist must prepare 550.0 mL of hydrochloric acid solution with a pH of 1.60 at 25 °C. He will do this in three steps: Fill a 550.0 mL volumetric flask about halfway with distilled water. Measure out a small volume of concentrated (8.0 M) stock hydrochloric acid solution and add it to the flask. Fill the flask to the mark with distilled water. Calculate the volume of concentrated hydrochloric acid that the chemist must measure out in the second step. Round your answer to 2 significant digits.</em>
Step 1: Calculate [H⁺] in the dilute solution
We will use the following expresion.
pH = -log [H⁺]
[H⁺] = antilog - pH = antilog -1.60 = 0.0251 M
Since HCl is a strong monoprotic acid, the concentration of HCl in the dilute solution is 0.0251 M.
Step 2: Calculate the volume of the concentrated HCl solution
We want to prepare 550.0 mL of a 0.0251 M HCl solution. We can calculate the volume of the 8.0 M solution using the dilution rule.
C₁ × V₁ = C₂ × V₂
V₁ = C₂ × V₂/C₁
V₁ = 0.0251 M × 550.0 mL/8.0 M = 1.7 mL
