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nikklg [1K]
3 years ago
8

What can change scientific knowledge?

Physics
1 answer:
Bezzdna [24]3 years ago
4 0
<span>Scientific knowledge changes with the growth of accumulated knowledge, technology, and greater experimentation. With further experimentation and more technology allowing more detailed experimentation, scientific knowledge constantly grows and changes.</span>
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When iron combines with oxygen to form iron oxide, a chemical reaction has occurred.
REY [17]
It is true for this question
6 0
3 years ago
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What is the best approximate value for the elastic potential energy (EPE) of the spring elongated by 3.0 meters?
klasskru [66]

P.E=0.0675 J

Explanation:

Elastic potential Energy=Force × distance of displacement

The formula to apply is;

P.E=1/2 ks²

where k is the spring constant given as; 1.5 *10^-2 N/m  and s is the displacement

In this case,

s=3

P.E= 1/2 * 1.5 × 10^-2 ×3²

P.E=1.5×10^-2*4.5

P.E=0.0675 J

Learn More

Elastic potential energy:brainly.com/question/1352053

Keywords: approximate,value,elastic potential energy,spring, elongated

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7 0
3 years ago
A boy is pulling a box on the ground by a string to the right. What four forces he using?
kirill115 [55]
The strong force in his body
3 0
3 years ago
A sound wave has a frequency of 300 Hz. If the wavelength is .50 m, then what is the speed of
kherson [118]

Answer:

15000 m/s

Explanation:

You just need to multiply the wavelength with the frequency.

7 0
3 years ago
Un cuerpo de 480 g de masa es atraído con una fuerza de 3.9 E-6 N por otro cuerpo de 196 g de masa. Calcula la distancia a la qu
Soloha48 [4]

Answer:

La distancia entre los dos cuerpos es aproximadamente 1.269 milímetros.

Explanation:

Asumamos que ambos cuerpos son partículas, la fuerza de atracción (F), en newtons, entre ambos cuerpos se define mediante la Ley de Newton de la Gravitación Universal, cuya ecuación es:

F = G \cdot \frac{m_{1}\cdot m_{2}}{r^{2}} (1)

Donde:

G - Constante de la gravitación universal, en metros cúbicos por kilogramo-segundo cuadrado.

m_{1}, m_{2} - Masas de los cuerpos, en kilogramos.

r - Distancia entre los cuerpos, en metros.

Si sabemos que G = 6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}}, m_{1} = 0.48\,kg, m_{2} = 0.196\,kg y F = 3.9\times 10^{-6}\,N, entonces la distancia entre los dos cuerpos es:

r = \sqrt{\frac{G\cdot m_{1}\cdot m_{2}}{F} }

r \approx 1.269\times 10^{-3}\,m

Es decir, la distancia entre los dos cuerpos es aproximadamente 1.269 milímetros.

5 0
3 years ago
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