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Rina8888 [55]
4 years ago
15

What are organelles? Describe the role of two organelles within the cell.

Physics
1 answer:
zloy xaker [14]4 years ago
4 0
Organelles are small structures found in cells that carry out certain tasks. Two examples of organelles are the Nucleus and the Mitochondria. Think of the nucleus as the brain of its cell, it controls activities and it contains a majority of the cells genetic material. The mitochondria is the part of the cells tasked with cellular respiration, which is the act of taking nutrients from a cell and turning it into energy.
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Someone please help me with this physics!
Taya2010 [7]
When it leaves the hand, it's rising at 18.2 m/s. After 1 second, gravity has slowed it to (18.2 - 9.8) = 8.4 m/s, still rising. Its average speed during the first second is 1/2 of (18.2 + 8.4) = 13.3 m/s. Rising for 1 second at an average speed of 13.3 m/s, it rises 13.3m from the hand.
8 0
3 years ago
Particles q1 = -53.0 uc, q2 = +105 uc, and
Nimfa-mama [501]

Answer:

-180.38\ \text{N}

Explanation:

q_1=-53\ \mu\text{C}

q_2=105\ \mu\text{C}

q_3=-88\ \mu\text{C}

r = Distance between the charges

r_{12}=0.5\ \text{m}

r_{23}=0.95\ \text{m}

r_{13}=1.45\ \text{m}

k = Coulomb constant = 9\times 10^9\ \text{Nm}^2/\text{C}^2

Net force is given by

F=F_{12}+F_{13}\\\Rightarrow F=\dfrac{kq_1q_2}{r_{12}^2}+\dfrac{kq_1q_3}{r_{13}^2}\\\Rightarrow F=kq_1(\dfrac{q_2}{r_{12}^2}+\dfrac{q_3}{r_{13}^2})\\\Rightarrow F=9\times 10^9\times (-53\times 10^{-6})(\dfrac{105\times 10^{-6}}{0.5^2}+\dfrac{-88\times 10^{-6}}{1.45^2})\\\Rightarrow F=-180.38\ \text{N}

The force on the particle q_1 is -180.38\ \text{N}.

8 0
3 years ago
Two particles are moving along the x axis. Particle 1 has a mass m₁ and a velocity v₁ = +4.7 m/s. Particle 2 has a mass m₂ and a
nirvana33 [79]

Answer:

m₁ / m₂ = 1.3

Explanation:

We can work this problem with the moment, the system is formed by the two particles

The moment is conserved, to simulate the system the particles initially move with a moment and suppose a shock where the particular that, without speed, this determines that if you center, you should be stationary, which creates a moment equal to zero

    p₀o = m₁ v₁ + m₂ v₂

    pf = 0

    m₁ v₁ + m₂ v₂ = 0

    m₁ / m₂ = -v₂ / v₁

    m₁ / m₂=  - (-6.2) / 4.7

     m₁ / m₂ = 1.3

Another way to solve this exercise is to use the mass center relationship

    Xcm = 1/M    (m₁ x₁ + m₂ x₂)

We derive from time

   Vcm = 1/M   (m₁ v₁ + m₂v₂)

As they say the velocity of the center of zero masses

    0 = 1/M   (m₁ v₁ + m₂v₂)

   m₁ v₁ + m₂v₂ = 0

    m₁ / m₂ = -v₂ / v₁

   m₁ / m₂ = 1.3

4 0
3 years ago
Which is not part of nuclear chemistry? A. Strong nuclear force B. Double-replacement reactions C. Radioactivity D. Nuclear deca
ziro4ka [17]

The correct choice is

B. Double-replacement reactions

in this type of reaction , two ionic compounds react and swaps their cations or anions giving two new compounds in the product. hence the double replacement reactions does not deal with the nucleus. all other terms like strong nuclear forces, radioactivity and nuclear decay deal with the nucleus.

8 0
4 years ago
Read 2 more answers
What is the square root of 25x10^12
kirill115 [55]

\sqrt{25 \times 10^{12} }

In order to find it's square root, we could make it into two square roots.

\sqrt{25 \times 10^{12} } = \sqrt{25} \times \sqrt{10^{12}}

Let us find the square roots of both radicals seprately.

\sqrt{25} =\sqrt{5*5}=5

Each  pair  of a number inside square root gives a number out .

\sqrt{10^{12}} = \sqrt{10*10*10*10*10*10*10*10*10*10*10*10}   \ \ ( \ makes \ 6 \ pairs \ of \ 10 )

\sqrt{10*10*10*10*10*10*10*10*10*10*10*10} = 10*10*10*10*10*10

= 10^6.

Therefore,

\sqrt{25 \times 10^{12} }=\sqrt{25} \times \sqrt{10^{12}}={5 \times 10^6}

\sqrt{25 \times 10^{12} } = {5 \times 10^6}

7 0
3 years ago
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