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lilavasa [31]
2 years ago
9

an 1800-w toaster, a 1400-w electric frying pan, and a 75-w lamp are plugged into the same outlet in a 15-a, 120-v circuit. (the

three devices are in parallel when plugged into the same socket.) what current is drawn by the electric frying pan?
Physics
1 answer:
Gnom [1K]2 years ago
8 0

The current drawn by the electric frying pan is <u>27.295 A.</u>

<u />

Power of toaster, P1 = 1800 W

Power of electric frying pan, P2 = 1400 W

Power of lamp, P3 = 75 W

Three devices are in parallel combination. So their Voltage difference is the same.

∆V = 120 Volt

Current is drawn by frying pan, I1 = P1/∆V = 1800/120 = 15 A

Current drawn by an electric frying pan, I2= 1400/120 = 11.67 A

Current drawn by frying pan, I3 = P3/120 = 75/120 = 0.625 A

Total current frying pan= (15 + 11.67 + 0.625) = 27.295 A

Electric current refers to the float of electricity in an electronic circuit, and to the amount of strength flowing via a circuit. it is measured in amperes (A). the bigger the price in amperes, the greater electricity is flowing inside the circuit.

The current is the charge of glide of price across a cross-segment every day to the direction of the float of the current. The S.I. unit of modern is coulomb consistent with 2d which is called ampere and denoted by means of A.

Learn more about current here:-brainly.com/question/24858512

#SPJ4

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V125BC [204]

Answer:

her arm when she is throwing it

Explanation:

because that is the action

7 0
3 years ago
Suppose a rock is dropped off a cliff with an initial speed of 0m/s. What is the rocks speed after 5 secounds, in m/s, if it enc
Tasya [4]

Answer:

The rock's speed after 5 seconds is 98 m/s.

Explanation:

A rock is dropped off a cliff.

It had an initial velocity of 0 m/s. And now it is moving downwards under the influence of gravitational force with the gravitational acceleration of 9.8 m/s².

Speed after 5 seconds = V

We know that acceleration = average speed/time

In our case,

g = ((0+V)/2)/5

9.8*5 = V/2

=> V = 2*9.8*5

V = 98 m/s

3 0
3 years ago
Read 2 more answers
At one instant, point P is 7.30 to the left of a proton that is moving at 3.10 km/s in vacuum. The point and velocity vector lie
o-na [289]

Answer:

the unit vector points from the point charge toward where the field is measured(from proton to point P)

Explanation:

8 0
3 years ago
N 1800kg car has an<br> of 3.8m/s? What is it<br> on the car?<br> acceleration<br> force acting
nevsk [136]

Answer:

6840 N

Explanation:

The force acting on the car can be found by using Newton's second law:

F = ma

where

F is the net force on the car

m is the mass of the car

a is its acceleration

For the car in this problem,

m = 1800 kg

a=3.8 m/s^2

Substituting,

F=(1800)(3.8)=6840 N

7 0
3 years ago
Sally runs 10,000 meter race at an average speed of 3.5m/s what does average speed mean
aleksandr82 [10.1K]

Answer:

The average speed of 3.5 m/s means that it takes Sally approximately 47.619 minutes to run 10,000 meters

Explanation:

Average speed is a scalar quantity that is given by dividing the total distance moved or traveled by an object by the time that it takes the object during the motion

The average peed indicates the rate at which the object makes a given amount of journey distance given that the journey is completed with varying speeds

With the knowledge of the average speed and the distance covered, the time for completion of the journey can be found as follows;

Average \ speed , \overline v = \dfrac{\Delta x}{\Delta t}

Where

\overline v = Average speed of the object = 3.5 m/s

Δt = The time it takes the Sally to run 10,000 meters

Δx = The total distance Sally runs = 10,000 meters

Therefore;

\Delta t = \dfrac{\Delta x}{ \overline v} = \dfrac{10,000 \ m}{3.5 \ m/s}  = \dfrac{20,000}{7} \ s \approx 2,857.143 \ s

The time it takes the Sally to run 10,000 meters= Δt = 20,000/7 seconds ≈ 2,857.143 seconds

20,000/7 seconds ≈ 47.619 minutes

Therefore, the average speed of 3.5 m/s means that the time it takes the Sally to run 10,000 meters ≈ 47.619 minutes

5 0
3 years ago
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