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Jobisdone [24]
4 years ago
14

Object A has of mass 7.20 kilograms, and object B has a mass of 5.75 kilograms. The two objects move along a straight line towar

d each other with velocities +2.00 meters/second and -1.30 meters/second respectively. What is the total kinetic energy of the objects after the collision, if the collision is perfectly elastic?
19.3 joules
21.9 joules
38.5 joules
43.0 joules
50.8 joules
Physics
1 answer:
Vera_Pavlovna [14]4 years ago
8 0
If the collision is elastic, there is no loss in kinetic energies, which means that the total energies before and after impact are the same.  So no need to worry about final velocities.

Final energy
= initial energy
= (1/2) (7.20*2.00^2+5.75*(-1.30)^2)
=19.26 joules

Answer: the total kinetic energy is 19.3 J. after collision.

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A charged comb often attracts small bits of dry paper that then fly away when they touch the comb. Explain why that occurs.
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A 50.0kg bicyclist on a 10.0kg bicycle speeds up from a 5.00m/s to 10.0m/s
goldenfox [79]

Answer:

  1. The total kinetic energy before accelerating = 750 J
  2. The total kinetic energy after accelerating = 3,000 J
  3. Total work done = 2,250 J

Explanation:

Given:

Mass of bicyclist = 50 kg

Mass of bicycle = 10 kg

Initial velocity (u) = 5 m/s

Final velocity (v) = 10 m/s

Find:

(a) What was the total kinetic energy before accelerating = ?

(b) What was the total kinetic energy after accelerating = ?

(c) How much work was done to increase the kinetic energy of the bicyclist = ?

Computation:

Total mass (M) = 50 kg + 10 kg = 60 kg

1. The total kinetic energy before accelerating = 1/2[Mu²]

The total kinetic energy before accelerating = 0.5[(60)(5)²]

The total kinetic energy before accelerating = 750 J

2. The total kinetic energy after accelerating = 1/2[Mv²]

The total kinetic energy after accelerating = 0.5[(60)(10)²]

The total kinetic energy after accelerating = 3,000 J

3. Total work done = Δ K.E

Total work done = 3,000 J - 750 J

Total work done = 2,250 J

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Answer:

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Explanation:

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