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Maksim231197 [3]
3 years ago
10

Which is closest to the volume of a cylinder with a height of 11 inches and

Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
4 0

Answer:

The closest to the volume of cylinder is <u>63 in.³</u>.

Step-by-step explanation:

Given:

Cylinder with a height of 11 inches and  a circumference of 8 1/2 inches.

Now, to find the volume.

As circumference is given we get the radius by putting formula:

Circumference = 8 1/2 inches = 17/2 inches.

Let the radius be r.

Circumference=2\pi r

<em>Taking the value of π = 3.14.</em>

\frac{17}{2}=2\times 3.14\times r

8.5=6.28\times r

<em>Dividing both sides by 6.28 we get:</em>

1.35=r

So, radius = 1.35 inches.

Height = 11 inches.

Now, putting the formula to get the volume:

Volume=\pi r^2h

Volume=3.14\times 1.35^2\times 11

Volume=3.14\times 1.8225\times 11

Volume=3.14\times 20.0475

Volume=62.949\ inches^3

<u><em>Hence, the volume of cylinder = 63 inches³ (approximately).</em></u>

Therefore, the closest to the volume of cylinder is 63 in.³.

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I WILL GIVE BRAINLIEST PLEASE HELP!!!
forsale [732]

A. side AB = 38/3 units B.m∠VYX =77°

Step-by-step explanation:

A.A rhombus has its four sides equal. This means side AB=side CD

Given that AB=5x+1 and CD=2x+8  equate the two sides to find value of x as;

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B.

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In a rhombus all four sides are equal, thus side VY = YX.This means triangle VYX is an isosceles triangle.

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∠VYX= 180°-(51.5°+51.5°)

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Learn More

Properties of a Rhombus : brainly.com/question/1305249

Keywords : Rhombus, fraction, simplest form

#LearnwithBrainly

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