Answer:
m∠R=76°
Step-by-step explanation:
∠STR=∠RST=(2x+2)° (base angles of isos triangle)
2(2x+2)+(3x+1)=180 (angle sum of triangle)
4x+4+3x+1=180
7x+5=180
7x=180-5
=175
x=175÷7
=25
Hence, m∠R = (3x+1)°
= [3(25)+1]°
= (75+1)°
= 76°
3x + 6 = -1 - 3 + 4x
Combine like terms on the right side.
3x + 6 = -4 + 4x
Add 4 to both sides.
3x + 10 = 4x
Subtract 3x from both sides.
10 = x
The equation has one solution (10).
The answer is C i think though
Given:
JKLM: J(8,4) ; K(4,10) ; L(12,12) ; M(14,10)
I'll just use the first vertex of every quadrilateral in comparison with J(8,4)
A(-8,-4) ; B(-4,-10) ; C(-12,-12) ; D(-14,-10) → a sequence of reflections across the x and y-axes, in any order. This is easy because each vertex has the same number but different signs.
E(11,2) ; F(7,8) ; G(15,10) ; H(17,8) → a translation of 3 units left and 2 units up. As you can envision with a graph, from 11 to 8, you need to move to the left of the x-axis. from 2 to 4, you need to move up of the y-axis.
O(6,7) ; P(2,13) ; Q(10,15) ; R(12,13) → a translation 2 units right and 3 units down. From 6 to 8 of the x-axis and from 7 to 4 of the y axis.
S(4,16) ; T(10,20) ; U(12,12) ; V(10,10) → This one has no pair but it seems as though this is rotated along the point U.
W(11,7) ; X(7,13) ; Y(15,15) ; Z(17,13) → a translation 3 units down and 3 units left.
