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3 years ago

What are the solutions of 2x2 3x = -5?

Mathematics

2 answers:

erma4kov [3.2K]3 years ago

8 0

Your answer is:::

-3 + i √31 over 4

-3 - i √31 over 4

Mama L [17]3 years ago

7 0

I'm guessing the equation is 2x^2-3x=-5
If this is the case, then you need to set the equation to equal 0 by moving the -5 to the left side of it
2x^2-3x+5=0
The you can factor the equation
(2x-5)(x+1)=0
now solve for each factor
2x-5=0 is x=5/2x
x+1=0 is x=-1

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Ivanshal [37]

Not sure sorry I’m not good at math need help with something else..

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3 years ago

Circle O, with center (x, y) passes through the points A(0, 0), B(-3, 0), and C(1, 2). Find the coordinates of the center of the

KonstantinChe [14]

Answer:

The center of the circle is

$(-\frac{3}{2},2)$

Step-by-step explanation:

Let the equation of the circle be

$x^2+y^2+2ax+2by+c=0$ , where (-a,-b) is the center of this circle.

The points lying the circle must satisfy the equation of this circle.

A(0,0)

We substitute this point to get;

$0^2+0^2+2a(0)+2b(0)+c=0$

$\implies c=0$

B(-3,0)

$(-3)^2+0^2+2a(-3)+2b(0)+c=0$

$\implies 9+0-6a+0+c=0$

$\implies -6a+c=-9$

But c=0

$\implies -6a=-9$

$\implies a=\frac{3}{2}$

C(1,2)

$1^2+2^2+2a(1)+2b(2)+c=0$

$1+4+2a+4b+c=0$

$2a+4b+c=-5$

Put the value of 'a' and 'c' to find 'b'

$2(\frac{3}{2})+4b+0=-5$

$3+4b+0=-5$

$4b=-5-3$

$4b=-8$

b=-2

Hence the center of the circle is

$(-\frac{3}{2},2)$

8 0

3 years ago

I need help with this Algebra 1 Study Guide. It has 5 questions . This has many hard questions so to you people that like a chal

scoundrel [369]

1. Rational numbers can be written as a ratio (fraction)
Whole numbers are rational. 5 = 5/1, for example.
Square roots are NOT rational. Example: √3
However, square roots of square numbers can be simplified, and are therefore rational. √4 = 2, rational.

√4 + √16 = 2 + 4 = 6. rational
√5 + √36... irrational
√9 + √24... irrational
2 × √4 = 2 × 2 = 4. rational
√49 × √81 = 7 × 9 = 63. rational
3√12... irrational

2. $n^\frac12=\sqrtn$
$9^\frac32=9^3\times\frac12=\sqrt{9^3}=\sqrt{729}=29$

3. $\frac{n^a}{n^b}=n^{a-b}$

$\frac{a^\frac13}{a^\frac14}=a^{\frac13-\frac14}=a^{\frac{1}{12}}$

4. $n^\frac1x=\sqrt[x]n$

$\sqrt[3]{m^2n^5}=m^{\frac23}n^{\frac53}$

5. $\sqrt{a}\times\sqrt{b}=\sqrt{ab}$

$\sqrt{3}\times\sqrt{12}=\sqrt{3\times12}=\sqrt{36}=6$

A, since neither 3 nor 12 is a square but we end up with 6.

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3 years ago

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sleet_krkn [62]

True. maths is applied in every day life for instance in science and accounting and as well as when daily with money

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Andrej [43]

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3 years ago

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