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2 years ago

What are the solutions of 2x2 3x = -5?

Mathematics

2 answers:

erma4kov [3.2K]2 years ago

8 0

Your answer is:::

-3 + i √31 over 4

-3 - i √31 over 4

Mama L [17]2 years ago

7 0

I'm guessing the equation is 2x^2-3x=-5
If this is the case, then you need to set the equation to equal 0 by moving the -5 to the left side of it
2x^2-3x+5=0
The you can factor the equation
(2x-5)(x+1)=0
now solve for each factor
2x-5=0 is x=5/2x
x+1=0 is x=-1

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A researcher conducts a hypothesis test using a sample of n = 40 from an unknown population. What is the df value for the t stat

aliya0001 [1]

Answer:

Correct option: b 39.

Step-by-step explanation:

A one-sample (or one mean) t-test is applied to test whether the population-parameter is significantly different from some hypothetical value.

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df = n - 1

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3 years ago

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3 years ago

A company that makes shampoo wants to test whether the average amount of shampoo per bottle is 16 ounces. The standard deviation

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Answer:

The correct option is 16.041 ounces.

Step-by-step explanation:

A single mean test can be used to determine whether the average amount of shampoo per bottle is 16 ounces.

The hypothesis can be defined as:

H₀: The average amount of shampoo per bottle is 16 ounces, i.e. μ = 16.

Hₐ: The average amount of shampoo per bottle is different from 16 ounces, i.e. μ ≠ 16.

The information provided is:

$n=64\\\sigma=0.20\\\alpha =0.10$

We can compute a 90% confidence interval to determine whether the population mean is 16 ounces or not.

Since the population standard deviation is known we will compute the z-interval.

The critical value of z for 90% confidence interval is:

$z_{0.05}=1.645$

*Use a z-table.

Compute the 90% confidence interval for population mean as follows:

$CI=\bar x\pm z_{\alpha/2}\times\frac{\sigma}{\sqrt{n}}\\$

Since the sample size is quite large, according to the law of large numbers the on increasing the sample size, the mean of the sample approaches the whole population mean.

So, the 90% confidence interval estimate for sample mean is:

$CI=\mu\pm z_{\alpha/2}\times\frac{\sigma}{\sqrt{n}}\\=16\pm 1.645\times \frac{0.20}{\sqrt{64}}\\=16\pm0.041125\\=(15.958875, 16.041125)\\\approx (15.959, 16.041)$

Thus, the correct option is 16.041 ounces.

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3 years ago