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suter [353]
3 years ago
6

A ____ by a design professional is used to determine the best system to provide the appropriate level and type of protection.

Computers and Technology
1 answer:
AleksAgata [21]3 years ago
8 0
A HAZARD EVALUATION by a design professional is used to determine the best system to provide the appropriate level and type of protection. Hazard evaluation involves systematic identification and analysis of hazards that are associated with a particular product or process. This gives one the opportunity to avoid these hazards.  
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What will be displayed in the console when this program runs?
Novay_Z [31]

Answer:

20 will be displayed on the console.

Explanation:

Given code is:

var numList = [10,20,30];

console.log(numList[numlist.length-2]);

The first line of code declares an array named numList and assigns it values given in the square brackets.

The second line of code is written to display the element on the index obtained by [numlist.length-2]

[numlist.length-2] means the second index.

Hence,

after running the code on JavaScript editor and dry running the code

20 will be displayed on the console.

7 0
3 years ago
Read 2 more answers
When testing a game, why might you consider throttling the game’s “frames per second”?
Ivenika [448]

Answer:

because if you throttle it then

you can make sure it's okay

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2 years ago
During the troubleshooting of a pc that will not boot, it is suspected that the problem is with the ram modules. the ram modules
Damm [24]
The modules were somehow disconnected
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4 years ago
In a typical e-mail address, the "host" is user: which one of the following word processing features saves you the most time whe
gayaneshka [121]
Find-and-replace . hope this helps !
4 0
3 years ago
Write an if-else statement that displays 'Speed is normal' if the speed variable is within the range of 24 to 56. If the speed v
kari74 [83]

Answer:

import java.util.Scanner;

public class Speed{

int speed;

public Speed(int speed){

this.speed = speed;

}

public void checkSpeed(){

if(speed >= 24 || speed <= 56){

System.out.println("Speed is normal");

}

else

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}

public static void main(String...args){

Scanner input = new Scanner(System.in);

int userSpeed = 0;

System.out.println("Enter a speed: ");

userSpeed = input.nextInt();

Speed obj1 = new Speed(userSpeed)

obj1.checkSpeed();

}

Explanation:

4 0
4 years ago
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