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choli [55]
3 years ago
5

Which of the following is the term for one possible form of the gene for a particular trait? A. allele B. codon C. autosomal tra

it D. sex-linked trait
Biology
2 answers:
jeka57 [31]3 years ago
6 0
Hello There!

If i remember correctly, the answer is A. allele.

Hope This Helps You!
Good Luck :) 

- Hannah ❤
Phantasy [73]3 years ago
5 0

Answer:

In this case the correct answer is the allele

Hello!

Let's solve this!

An allele is each of the two versions of a gene that is one of the father and one of the mother.

A codon is a triplet of nitrogen bases that bind with the anticodon.

Autosomal trait is a trait that both alleles must have in order for it to manifest.

Trait linked to sex are the traits transmitted on the sex chromosomes.

In this case the correct answer is allele

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En un cruce entre peces naranjas y peces grises se obtiene una generación (f1) de 50% peces grises . Realice el cruce y explique
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Answer:

Uno de los progenitores es heterocigoto para color naranja (Nn) y el otro parental es homocigoto recesivo para gris (nn). Al haber una cruza entre un homocigoto recesivo y un heterocigoto, la 50% de la progenie expresa color naranja (Nn), mientras que el otro 50% expresa color gris (nn).

Explanation:

<u>Datos disponibles:</u>

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Podemos nombrar el alelo dominante para color naranja <em>N</em>, y al alelo recesivo  para color gris <em>n</em>.

Para que en un cruce entre dos fenotipos distintos, el 50% de la primer camada exprese uno de estos fenotipos, entonces uno de los parentales debe ser heterocigoto, mientras que el otro parental debe ser homocigoto recesivo. De esta forma 50% de la primera generación expresara uno de los fenotipos, mientras que el otro 50% expresará el otro fenotipo.

Supongamos que uno de los parentales lleva el genotipo <em>Nn</em>, y el otro parental es <em>nn</em>.

Cruce:

Parental)      Nn    x     nn

Gametas)   N    n       n    n

Fenotipos) Naranja     Gris

Cuadro de Punnett)      N           n

                            n       Nn         nn

                            n       Nn         nn

F1)  2/4 = 1/2 = 50% de la progenie tendrá genotipo heterocigoto, Nn

     2/4 = 1/2 = 50% de la progenie tendrá genotipo homocigota recesivo,    

     nn

     50% de la progenie será color naranja (Nn)

     50% de la progenie será color gris (nn)

               

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