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Mrrafil [7]
3 years ago
15

What is the value of h?

Mathematics
2 answers:
hoa [83]3 years ago
7 0
This is a 45-45-90 special right triangle, the hypotenuse is √2 times the leg. (the two legs are equal.) so the answer is 8√2
Naya [18.7K]3 years ago
5 0

Answer:

1.D 2.C 3.A 4.A 5.C 6.B, Connections Special Right Triangles Practice.

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Which of the following statements is true about the given function?
Maslowich
I think the answer is c
4 0
3 years ago
Read 2 more answers
*BEST ANSWER WILL BE MARKED BRAINLIEST*
Gwar [14]
Alright

for a 45-45-90 triangle, if the legs are x then the hytponuse is x√2


so LM=x√2 is right
NM=x

also, tan=oposite side/adjacent side
so that would be LN/MN or MN/LN=x/x=1

so that would be tan(45)=1

so you want to check the 1st one, 3rd one and 5th one

NM=x
LM=x√2
tan(45°)=1 are the answers
4 0
3 years ago
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f the price charged for a candy bar is​ p(x) cents, where p (x )equals 162 minus StartFraction x Over 10 EndFraction ​, then x t
andreev551 [17]

Answer:

a. 1620-x^2

b. x=810

c. Maximum value revenue=$656,100

Step-by-step explanation:

(a) Total revenue from sale of x thousand candy bars

P(x)=162 - x/10

Price of a candy bar=p(x)/100 in dollars

1000 candy bars will be sold for

=1000×p(x)/100

=10*p(x)

x thousand candy bars will be

Revenue=price × quantity

=10p(x)*x

=10(162-x/10) * x

=10( 1620-x/10) * x

=1620-x * x

=1620x-x^2

R(x)=1620x-x^2

(b) Value of x that leads to maximum revenue

R(x)=1620x-x^2

R'(x)=1620-2x

If R'(x)=0

Then,

1620-2x=0

1620=2x

Divide both sides by 2

810=x

x=810

(C) find the maximum revenue

R(x)=1620x-x^2

R(810)=1620x-x^2

=1620(810)-810^2

=1,312,200-656,100

=$656,100

7 0
3 years ago
Determine the value of x
Brut [27]
It’s d brrooooooooooooo
6 0
2 years ago
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What is the Range of this Graph? ASAP
Flura [38]

Answer:

The range would be {-4,-3,1,6}

Step-by-step explanation:

Individual points are bracketed

6 0
3 years ago
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