$678.58 if u can give me brainliest thx! :)
Answer: 0.0793
Step-by-step explanation:
Let the IQ of the educated adults be X then;
Assume X follows a normal distribution with mean 118 and standard deviation of 20.
This is a sampling question with sample size, n =200
To find the probability that the sample mean IQ is greater than 120:
P(X > 120) = 1 - P(X < 120)
Standardize the mean IQ using the sampling formula : Z = (X - μ) / σ/sqrt n
Where; X = sample mean IQ; μ =population mean IQ; σ = population standard deviation and n = sample size
Therefore, P(X>120) = 1 - P(Z < (120 - 118)/20/sqrt 200)
= 1 - P(Z< 1.41)
The P(Z<1.41) can then be obtained from the Z tables and the value is 0.9207
Thus; P(X< 120) = 1 - 0.9207
= 0.0793
-36x+30
-24x+20
-18x+15
-12x+10
Answer:
7
Step-by-step explanation:
The left hand limit is when we approach zero from left. We use the function on this domain in finding the limit.
The right hand limit is
Since the left hand limit equals the right hand limit;
Answer:
78
Step-by-step explanation:
Mode = number that appears most in a set of numbers
The number that appears the most in this set is 78. So, the mode is 78. Hope it helps!
