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Elis [28]
3 years ago
9

For what values of x is the rational expression below undefined? x-7/x^2-7x-8

Mathematics
1 answer:
alekssr [168]3 years ago
5 0
We have

f(x)=(x-7)/(x²<span>-7x-8)

resolving the quadratic equation
using a graph tool-------- > see the attached figure
x=-1  x=8
therefore
</span>(x-7)/(x²-7x-8)=(x-7)/[(x+1)*(x-8)

the answer is  -1  and  8



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schepotkina [342]
Your answer would be 12
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The distance on the map between Yappy City and Quiet City is 23 cm. What is the actual distance between the cities? 5 cm : 2 mil
S_A_V [24]

The actual distance between the cities will be equal to 9.2 miles.

<h3>What is an arithmetic operation?</h3>

The four basic mathematical operations are the addition, subtraction, multiplication, and division of two or even more integers. Among them is the examination of integers, particularly the order of actions, which is crucial for all other mathematical topics, including algebra, data organization, and geometry.

As per the given data in the question,

Distance between Yappy city and quit city is 23 cm.

As per the conversion is given in the question,

5 cm = 2 miles

Then, the number of miles of distance will be,

x = (2 × 23)/5

x = 9.2 miles.

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3 0
1 year ago
Factor the expression.<br><br> 5x + 15<br><br> The factored expression is
Tresset [83]

Find the Greatest Common Factor (GCF)

GCF = 5

Factor out the GCF (Write the GCF first, and then in parenthesis, divide each term by the GCF.)

5(5x/5 + 15/5)

Simplify each term in parenthesis

<u>5(x + 3) </u>

8 0
3 years ago
A fair coin is tossed three times and the events A, B, and C are defined as follows: A: \{ At least one head is observed \} B: \
Yanka [14]

Answer:

a) P(A)=0.875

b) \text{P(A or B)}=0.875

c) \text{P((not A)  or B  or (not C))}=0.625

Step-by-step explanation:

Given : A fair coin is tossed three times and the events A, B, and C are defined as follows: A: At least one head is observed, B: At least two heads are observed, C: The number of heads observed is odd.

To find : The following probabilities by summing the probabilities of the appropriate sample points ?

Solution :

The sample space is

S={HHH,HHT,HTT,HTH,TTT,TTH,THH,THT}

n(S)=8

A: At least one head is observed

i.e. A={HHH,HHT,HTT,HTH,TTH,TTH,THH,THT}

n(A)=7

B: At least two heads are observed

i.e. B={HHH,HTT,TTH,THT}

n(B)=4

C: The number of heads observed is odd.

i.e. C={HHH,HTT,THT,TTH}

n(c)=4

a) Probability of A, P(A)

P(A)=\frac{n(A)}{n(S)}

P(A)=\frac{7}{8}

P(A)=0.875

b) P(A or B)

Using formula,

\text{P(A or B)}=P(A)+P(B)-\text{P(A and B)}

\text{P(A or B)}=\frac{n(A)}{n(S)}+\frac{n(B)}{n(S)}-\frac{\text{n(A and B)}}{n(S)}

\text{P(A or B)}=\frac{7}{8}+\frac{4}{8}-\frac{4}{8}

\text{P(A or B)}=\frac{7}{8}

\text{P(A or B)}=0.875

(c) P((not A)  or B  or (not C))

A={HHH,HHT,HTT,HTH,TTH,TTH,THH,THT}

not A = {TTT} = 1

B={HHH,HTT,TTH,THT}

C={HHH,HTT,THT,TTH}

not C = {HHT,HTH,THH,TTT} = 4

So, not A or B or not C = {HHH,HHT,HTH,THH,TTT}=5

\text{P((not A)  or B  or (not C))}=\frac{5}{8}

\text{P((not A)  or B  or (not C))}=0.625

4 0
3 years ago
Solve. 7(2y-10)=14. What is the awnser
Sergeu [11.5K]

Answer:

y = 6

Step-by-step explanation:

3 0
3 years ago
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