Answer:
n=9
Step-by-step explanation:
-5-4n=-41
+5 +5
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-4n=-36
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-4n/4=-36/-4
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n=9
Answer:
4.=11 5.=4 6.=17 7.=47 I think
Step-by-step explanation:
an absolute value of a number is never negative so you just make the number positive and go about the equation normally
The computation shows that the placw on the hill where the cannonball land is 3.75m.
<h3>How to illustrate the information?</h3>
To find where on the hill the cannonball lands
So 0.15x = 2 + 0.12x - 0.002x²
Taking the LHS expression to the right and rearranging we have:
-0.002x² + 0.12x -.0.15x + 2 = 0.
So we have -0.002x²- 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x² + 0.03x -2 = 0.
This is a quadratic equation with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25.
The second solution y = 0.15 * 25 = 3.75
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Complete question:
The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?
Answer:
a)
, n = 15 , X=3.4 , S=1.5 , α = .05
Formula : 
p- value = 0.607(using calculator)
α = .05
p- value > α
So, we failed to reject null hypothesis
b)
, n =75 , X=20.12 , S=2.1 , α = .10
Formula :
p- value = 0.000412(using calculator)
α = .1
p- value< α
So, we reject null hypothesis
(c) 
, n = 36, p-value = 0.061.
Assume α = .05
p-value = 0.061.
p- value > α
So, we failed to reject null hypothesis
Y = 3x - 7
just find the slope then use two point and point slope form to solve for slope intercept form
