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Advocard [28]
3 years ago
10

What is the answer please

Mathematics
1 answer:
Sophie [7]3 years ago
3 0

Answer:

i can't see it it's turned sideways, sorry!!!!!

Step-by-step explanation:

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A dilation with a scale factor of 4 is applied to the three line segments shown. The resulting images are P'Q', A'B', and M'N' D
alexira [117]

Answer:

1st into the 3rd 2nd into 1st 3rd into 3rd

Step-by-step explanation:

8 0
2 years ago
Find the square root of each.
DIA [1.3K]
169=13
144=12
Hope this helps and please give brainliest!
8 0
3 years ago
a tree 20 feet tall with a circumference of 3 ft has a vine wound around 7 times. How long is the vine?
FinnZ [79.3K]

If the tree is 20 feet tall with circumference 3 feet then the length of  vince is around 21 feet.

Given the height of tree is 20 feet and the circumference of tree is 3 feet.

We have to find the length of vine.

Circumference is the perimeter of a circular object. Because the trunk of a tree is in shape of circle so the perimeter of the trunk is 2πr.

We have been given the circumference of tree be 3 feet.

Circumference=2πr

Because vine is 7 times the circumference so the length of vine being:

Length of vine=7*3

=21 feet.

Hence if the tree is 20 feet tall with circumference 3 feet then the vince is around 21 feet long.

Learn more about circumference at brainly.com/question/20489969

#SPJ1

4 0
1 year ago
Read 2 more answers
Use lagrange multipliers to find the point on the plane x â 2y + 3z = 6 that is closest to the point (0, 2, 4).
Arisa [49]
The distance between a point (x,y,z) on the given plane and the point (0, 2, 4) is

\sqrt{f(x,y,z)}=\sqrt{x^2+(y-2)^2+(z-4)^2}

but since \sqrt{f(x,y,z)} and f(x,y,z) share critical points, we can instead consider the problem of optimizing f(x,y,z) subject to x-2y+3z=6.

The Lagrangian is

L(x,y,z,\lambda)=x^2+(y-2)^2+(z-4)^2+\lambda(x-2y+3z-6)

with partial derivatives (set equal to 0)

L_x=2x+\lambda=0\implies x=-\dfrac\lambda2
L_y=2(y-2)-2\lambda=0\implies y=2+\lambda
L_z=2(z-4)+3\lambda=0\implies z=4-\dfrac{3\lambda}2
L_\lambda=x-2y+3z-6=0\implies x-2y+3z=6

Solve for \lambda:

x-2y+3z=-\dfrac\lambda2-2(2+\lambda)+3\left(4-\dfrac{3\lambda}2\right)=6
\implies2=7\lambda\implies\lambda=\dfrac27

which gives the critical point

x=-\dfrac17,y=\dfrac{16}7,z=\dfrac{25}7

We can confirm that this is a minimum by checking the Hessian matrix of f(x,y,z):

\mathbf H(x,y,z)=\begin{bmatrix}f_{xx}&f_{xy}&f_{xz}\\f_{yx}&f_{yy}&f_{yz}\\f_{zx}&f_{zy}&f_{zz}\end{bmatrix}=\begin{bmatrix}2&0&0\\0&2&0\\0&0&2\end{bmatrix}

\mathbf H is positive definite (we see its determinant and the determinants of its leading principal minors are positive), which indicates that there is a minimum at this critical point.

At this point, we get a distance from (0, 2, 4) of

\sqrt{f\left(-\dfrac17,\dfrac{16}7,\dfrac{25}7\right)}=\sqrt{\dfrac27}
8 0
3 years ago
Four farmers are picking apples in an orchard. Farmer A picks 38 of the apples, Farmer B picks 22% of the apples, Farmer C picks
AfilCa [17]
The amount of apples picked by the farmers is:
Farmer A=38%=0.38
Farmer B=22%=0.22
Farmer C=0.29
Farmer D=0.2
Thus the order from the least to greatest by th number of apples they pick will be:
D,B,C,A
that is:
Farmer D, Farmer B, Farmer C, Farmer A
8 0
3 years ago
Read 2 more answers
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