1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Gwar [14]
4 years ago
6

X - 5y = -15 if x = -5

Mathematics
2 answers:
Inga [223]4 years ago
7 0

Answer:

<u><em>If x= -5 y=2</em></u>

Step-by-step explanation:

1. Plug in -5 in X then solve for Y

2. Solve for y

-5 - 5y = -15

-5y= -10

<u><em>y= 2</em></u>

<u><em>Hope this helps!</em></u>

Juli2301 [7.4K]4 years ago
3 0

Answer:

y = 2

Step-by-step explanation:

First, put the <em>-5 in for x</em>:

-5 - 5y = -15

Then, <em>add five to both sides</em> to get - 5y by itself:

-5y = -10

Finally, <em>divide both sides by -5</em> to get y:

y = 2

You might be interested in
Pleaseeeeee helppppp, ill give you brainley i promise
Dima020 [189]
Its the third one for the answer
8 0
3 years ago
What is partitive? Give an example!
Advocard [28]
Partitive and Quotitive Division. An important distinction in division is between situations that call for a partitive (also called fair share or sharing) model of division, and those that call for a quotitive (also called subtraction or measurement) model of division.
4 0
4 years ago
Which of the following functions f : {0, 1, 2, 3} ! {0, 1, . . . , 7} are one-to-one?
allsm [11]

Answer:

1. No.

f(0)=0\\1^2=1; \text{then } f(1)=1\\2^2=4\equiv 4 \text{ mod 8}; \text{then } f(2)=4\\3^2=9\equiv 1 \text{mod 8 }; \text{then } f(3)=1

Since f(1)=f(3) and 1\neq 3 then f isn't one-to-one.

2. No

f(0)=0\\1^3=1\equiv 1\text{ mod 8}; \text{then } f(1)=1\\2^3=8\equiv 0\text{ mod 8}; \text{then } f(2)=0\\3^3=27\equiv 3 \text{ mod 8}; \text{then } f(3)=3

Since f(0)=f(2) and 0\neq 2 then f isn't one-to-one.

3. No

0^3-8=-8\equiv 0\text{ mod 8}; \text{then } f(0)=0\\1^3-8=-7\equiv 1\text{ mod 8}; \text{then } f(1)=1\\2^3-8=0\equiv 0 \text{ mod 8}; \text{then } f(2)=0\\3^3-8=27-8=19\equiv 3 \text{ mod 8}; \text{then } f(3)=3\\

Since f(0)=f(2) and 0\neq 2 then f isn't one-to-one.

4. Yes

0^3+2*0=0; \text{then } f(0)=0\\1^3+2*1=3\equiv 3\text{ mod 8};  \text{then } f(1)=3\\2^3+2*2=8+4=12\equiv 4 \text{ mod 8};  \text{then } f(2)=4\\3^3+2*3=27+6=33\equiv 1\text{ mod 8};  \text{then } f(3)=1

Since f(0)\neq f(1)\neq f(2) \neq f(3), then f is one-to-one

5. Since f(1)=f(3) and 1\neq 3 then, f isn't one-to-one

3 0
4 years ago
In 2018, Mike Krzyewski and John Calipari topped the list of highest paid college basketball coaches (Sports Illustrated website
expeople1 [14]

From the data given, we estimate the population mean and population standard deviation. Then, we use this estimate to find a 95% confidence interval for the population variance and the population standard deviation.

Sample:

Salaries in millions of dollars: 2.2, 1.5, 0.5, 1.3, 2.4, 1.5, 2.7, 0.3, 2.0, 0.3

Question a:

The mean is the sum of all values divided by the number of values. So

\overline{x} = \frac{2.2 + 1.5 + 0.5 + 1.3 + 2.4 + 1.5 + 2.7 + 0.3 + 2.0 + 0.3}{10} = 1.42

The sample mean salary is of 1.42 million.

Question b:

The standard deviation is the square root of the difference squared between each value and the mean, divided by one less than the number of values.

So

s = \sqrt{\frac{(2.2-1.42)^2 + (1.5-1.42)^2 + (0.5-1.42)^2 + (1.3-1.42)^2 + (2.4-1.42)^2 + (1.5-1.42)^2 + (2.7-1.42)^2 + ...}{9}} = 0.8772

Thus, the estimate for the population standard deviation is of 0.8772 million.

Question c:

The sample size is n = 10

The significance level is \alpha = 1 - 0.05 = 0.95

The estimate, which is the sample standard deviation, is of s = 0.8772.

Now, we have to find the critical values for the Pearson distribution. They are:

\chi^2_{\frac{\alpha}{2},n-1} = \chi^2_{0.025,9} = 19.0228

\chi^2_{1-\frac{\alpha}{2},n-1} = \chi^2_{0.975,9} = 2.7004

The confidence interval for the population variance is:

\frac{(n-1)s^2}{\chi^2_{\frac{\alpha}{2},n-1}} < \sigma^2 < \frac{(n-1)s^2}{\chi^2_{1-\frac{\alpha}{2},n-1}}

\frac{9*0.8772^2}{19.0228} < \sigma^2 < \frac{9*0.8772^2}{2.7004}

0.3641 < \sigma^2 < 2.5646

Thus, the 95% confidence interval for the population variance is (0.3641, 2.5646)

Question d:

Standard deviation is the square root of variance, so:

\sqrt{0.3641} = 0.6034

\sqrt{2.5646} = 1.6014

The 95% confidence interval for the population standard deviation is (0.6034, 1.6014).

For more on confidence intervals for population mean/standard deviation, you can check brainly.com/question/13807706

4 0
3 years ago
Help me with this math I gotta get some serious help
horsena [70]

Answer:

C

Step-by-step explanation:

3 0
3 years ago
Other questions:
  • Tom is trying to write 3/47 as a decimal. He used long division and divided until he got the quotient 0.0638297872, at which poi
    6·1 answer
  • paul was collecting cans for recycling. on saturday he filled six bags up and on sunday filled 4 more bags than saturday. if eac
    14·1 answer
  • 20×9×5 distributive property
    10·2 answers
  • (3 8) 1 = 3 (8 1) A.True B.False
    9·1 answer
  • Find the center and radius of x^2+y^2=9
    12·2 answers
  • How would I answer this equation 5y - 2y = 3y + 2
    6·1 answer
  • Reasoning can you name a real number that is represented by √-36? Explain
    6·2 answers
  • Please help me. Thank you
    9·1 answer
  • What is the polynomial in standard form ? <br><br><br>(X-4)(x-6)=
    9·1 answer
  • Caleb is saving money for a new skateboard. So far he has saved $18. The cost of the skateboard is 6 times as great as the amoun
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!