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neonofarm [45]
3 years ago
15

Help me with this math I gotta get some serious help

Mathematics
1 answer:
horsena [70]3 years ago
3 0

Answer:

C

Step-by-step explanation:

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Pls help ASAP
soldier1979 [14.2K]

Answer:

Sample response:

To determine the relationship between quantities, you must determine what to do to the x-values to make them into y-values. The correct operation must turn every x-value into the corresponding y- value in the table. Once you know the relationship, you can use the same operation on all of the x-values that have unknown y-values.

OR:

In a table to get from x to y you have to multiply by a number. To find this you must divide x by y or y by x. So to get the missing quantities you must multiply the last known number by the number you found by dividing.

3 0
3 years ago
Read 2 more answers
I really need help with this
marysya [2.9K]
I believe it is the first one
7 0
3 years ago
Last week Kristen bought 5 pounds of apples this week she bought 1 half of that amount how many pounds of apples did Kristen buy
Tema [17]

Last week he bought three apples for $3.90. The cost of an apple = 3.9/3 = 1.3 This week he bought 2 more apples which totals 5 for $6.50 The cost of each apple = 6.5/5 = 1.3. The cost of an apple in the two weeks is the same. Arnold bought more apples in the following week but there was a corresponding raise in price. When he bought fewer apples last week he never had to pay as much as he did the year later

7 0
4 years ago
Read 2 more answers
How do you work this out
Digiron [165]
Check the picture below.

notice, is just a circle inscribed in a square.

now for the first one, we know the diameter is 14, so the square is a 14x14, and the radius of that is half the diameter or 7.

now, if we get the area of the square, which includes the area of the circle, and THEN get the area of the circle and subtract it from the square's, what's leftover is the shaded section.

\bf \textit{area of a circle}\\\\ A=\pi r^2\\\\
-------------------------------\\\\
\stackrel{\textit{square's area}}{14\cdot 14}~-~\stackrel{\textit{circle's area}}{\pi 7^2}\implies 196-49\pi

now, for the one on the right-hand-side, the radius is 8, and square's area is 16x16,

\bf \stackrel{\textit{square's area}}{16\cdot 16}~-~\stackrel{\textit{circle's area}}{\pi 8^2}\implies 256-64\pi

5 0
4 years ago
Javier and his study group designed a word problem, equation, table, and graph that were all supposed to represent the same info
kow [346]

Graph is your answer look below for proof

have a good day!

                                                                     

3 0
3 years ago
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