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Gala2k [10]
3 years ago
12

Fiona draws a circle with a diameter of 14 meters. What is the area of Fiona’s circle? 7Pi meters squared 14Pi meters squared 28

Pi meters squared 49Pi meters squared
Mathematics
2 answers:
Katarina [22]3 years ago
8 0

Answer:

49 pi  meters squared

Step-by-step explanation:

radius =14/2=7 m

area=pi*r^2=pi*7^2=49 pi  meters squared

vitfil [10]3 years ago
6 0

Answer:

49Pi meters squared

Step-by-step explanation:

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The hypotenuse of a right triangle measures 10 inches, and the side opposite to ∠θ, one of the non-right angles, is 5 inches lon
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The measure of angle theta is 30 degrees. 

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Question 3
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Step-by-step explanation:

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3 years ago
Each of 16 students measured the circumference of a tennis ball by four different methods, which were: A: Estimate the circumfer
almond37 [142]

Answer:

Following are the solution to the given equation:

Step-by-step explanation:

Please find the complete question in the attachment file.

In point a:

\to \mu=\frac{\sum xi}{n}

       =22.8

\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}

       =\sqrt{\frac{119.18}{16-1}}\\\\ =\sqrt{\frac{119.18}{15}}\\\\ = \sqrt{7.94533333}\\\\=2.8187

In point b:

\to \mu=\frac{\sum xi}{n}

       =20.6875  

\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}

       =\sqrt{\frac{26.3375}{16-1}}\\\\=\sqrt{\frac{26.3375}{15}}\\\\ =\sqrt{1.75583333}\\\\ =1.3251

In point c:

 \to \mu=\frac{\sum xi}{n}

         =21  

\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}

       =\sqrt{\frac{2.62}{16-1}}\\\\ =\sqrt{\frac{2.62}{15}} \\\\= \sqrt{0.174666667}\\\\=0.4179

In point d:

\to \mu=\frac{\sum xi}{n}

       =20.8375  

\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}

       =\sqrt{\frac{8.2975}{16-1}}\\\\ =\sqrt{\frac{8.2975}{15}} \\\\  =\sqrt{0.553166667} \\\\ =0.7438

6 0
3 years ago
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