..........The answer is A
The answer is c hope i helped
To simply determine if the solution is true. Simply plug in and or substitute the values of w for the expression. Then see if the left hand side is equal to the right side of the equation.
The equation is
.
We are looking for a function with a vertex above the x-axis and a function that opens upward (has coefficient a > 0).
The first function opens downward and intersects the x-axis. The second function has a vertex below the x-axis. The third function satisfies our requirements. The fourth function has a vertex on the x-axis.
We can solve this algebraically with the knowledge that the real solutions of a quadratic are its x-intercepts. If there are no x-intercepts (because it lies entirely above or below the x-axis), then there are no real solutions. This is true when the discriminant
. You can see that from the quadratic formula. This holds true for both answers A and C, so to find the correct one, we remember that when the coefficient a of the
term is positive, the graph opens upwards, so we choose
C.
X⁶ + 1000
x⁶ - 10x⁴ + 10x⁴ + 100x² - 100x² + 1000
x⁶ - 10x⁴ + 100x² + 10x⁴ - 100x² + 1000
x²(x⁴) - x²(10x²) + x²(100) + 10(x⁴) - 10(10x²) + 10(10)
x²(x⁴ - 10x² + 100) + 10(x⁴ - 10x² + 100)
(x² + 10)(x⁴ - 10x² + 100)