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3 years ago

4. Simplify the following using the quotient rule of exponents:

Mathematics

1 answer:

7nadin3 [17]3 years ago

7 0

Answer:

31=1/1

33=1/1

30=3/10

3-=-3

Step-by-step explanation:

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T F IfA and B are similar matrices, then AT=BT

muminat

Answer:

Step-by-step explanation:

We know that for two similar matrices $A$ and $B$ exists an invertible matrix $P$ for which

$[tex]B = P^{-1} AP$ [/tex]

∴ $B^{T} = (P^{-1})^{T} A^{T} P^{T} \\$

Also $P^{-1}P = I\\$

and $(P^{-1})^{T} = (P^{T})^{-1}$

∴ $(P^{-1})^{T}P^{T} = I$

so, $B^{T} = (P^{-1})^{T} A^{T} P^{T} = (P^{T})^{-1}A^{T} P^{T}\\B^{T} = A^{T} I\\B^{T} = A^{T}$

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3 years ago

How do you solve this problem? What is a rewritten form of the radical(-8/726) It is supposed to be a squar root sign instead of

Mamont248 [21]

I think the answer is negative 8 square root 726

then the answer if I am right sorry if I am not would be negative 88 square root 6

again sorry if wrong

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2 years ago

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Alexeev081 [22]

Answer:

Can u show the whole question

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2 years ago

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Suppose Kaitlin places $6500 in an account that pays 12% interest compounded each year.

Leya [2.2K]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 1 year}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &1 \end{cases}$

$\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 1}\implies A=6500(1.12)\implies A=7280 \\\\[-0.35em] ~\dotfill$

$\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 2 years}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases}$

$\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 2}\implies A=6500(1.12)^2\implies A=8153.6$

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3 years ago

Write the expression: y divided by the quantity x minus 5.

mr Goodwill [35]

Answer:

please mark me brainiliest

y/x-5

Step-by-step explanation:

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3 years ago

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