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katrin2010 [14]
3 years ago
8

Need help ASAP

Mathematics
1 answer:
yan [13]3 years ago
3 0

Answer:

.5 or (1/2)

.5  or (1/2)

2.5 or (5/2)

Step-by-step explanation:

all you really have to do is mulitply the numbers by .5

1*.5= .5

5*.5= 2.5

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It is impossible to create a square pyramid by rotating a shape about an axis because its base is not ________.
natta225 [31]
It is impossible because it's base is not circular. A solid of revolution is <span>obtained by rotating a </span>plane curve<span> around some </span>straight line, that is, <span>the </span>axis of revolution that lies on the same plane. The closest to a square pyramid applying this concept is by rotating a right triangle around the opposite or adjacent side (the axis), but the shape that you get is a straight circular cone. 
7 0
3 years ago
HELP PLEASE. Two points are 17 units apart on a number line. The coordinate of one point is -20.
cluponka [151]

Answer: -37 & -3

Step-by-step explanation:

-20-17= -37

-20+17= -3

5 0
3 years ago
How many models of 100 do you need to model 3,200
atroni [7]
32 models of 100. you are prone for elementary questions in all subjects and i accept that very dearly, thank you
5 0
3 years ago
Read 2 more answers
Someone help please
Alla [95]

Answer:  Choice A

\tan(\alpha)*\cot^2(\alpha)\\\\

============================================================

Explanation:

Recall that \tan(x) = \frac{\sin(x)}{\cos(x)} and \cot(x) = \frac{\cos(x)}{\sin(x)}. The connection between tangent and cotangent is simply involving the reciprocal

From this, we can say,

\tan(\alpha)*\cot^2(\alpha)\\\\\\\frac{\sin(\alpha)}{\cos(\alpha)}*\left(\frac{\cos(\alpha)}{\sin(\alpha)}\right)^2\\\\\\\frac{\sin(\alpha)}{\cos(\alpha)}*\frac{\cos^2(\alpha)}{\sin^2(\alpha)}\\\\\\\frac{\sin(\alpha)*\cos^2(\alpha)}{\cos(\alpha)*\sin^2(\alpha)}\\\\\\\frac{\cos^2(\alpha)}{\cos(\alpha)*\sin(\alpha)}\\\\\\\frac{\cos(\alpha)}{\sin(\alpha)}\\\\

In the second to last step, a pair of sine terms cancel. In the last step, a pair of cosine terms cancel.

All of this shows why \tan(\alpha)*\cot^2(\alpha)\\\\ is identical to \frac{\cos(\alpha)}{\sin(\alpha)}\\\\

Therefore, \tan(\alpha)*\cot^2(\alpha)=\frac{\cos(\alpha)}{\sin(\alpha)}\\\\ is an identity. In mathematics, an identity is when both sides are the same thing for any allowed input in the domain.

You can visually confirm that \tan(\alpha)*\cot^2(\alpha)\\\\ is the same as \frac{\cos(\alpha)}{\sin(\alpha)}\\\\ by graphing each function (use x instead of alpha). You should note that both curves use the exact same set of points to form them. In other words, one curve is perfectly on top of the other. I recommend making the curves different colors so you can distinguish them a bit better.

6 0
3 years ago
Schaum earns (x4 + 16x) every month. His wife earns (3x4 + 11x) every
damaskus [11]

Given:

Schaum's earnings in a month = x^4+16x

His wife's earnings in a month = 3x^4+11x

Where x is the number of working days in a month.

To find:

The total earnings in a month.

Solution:

We know that,

Total earnings = Schaum earnings + His wife's earnings in a month

                       =x^4+16x+3x^4+11x

                       =(x^4+3x^4)+(16x+11x)

                       =4x^4+27x

Therefore, the correct option is A.

7 0
3 years ago
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