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Tju [1.3M]
3 years ago
12

In accounting, a company's gross profit rate measures how well the company controls cost of goods sold to maximize gross profit.

The gross profit rate, PPP, is calculated using the formula P = \dfrac{S - C}{S}P= S S−C ​ P, equals, start fraction, S, minus, C, divided by, S, end fraction, where SSS is the net sales and CCC is the cost of goods sold. Rearrange the formula to solve for the cost of goods sold (C)(C)left parenthesis, C, right parenthesis. C=C=C, equals What is the cost of goods sold if the net sales is \$1{,}200{,}000$1,200,000dollar sign, 1, comma, 200, comma, 000 and the gross profit ratio is 0.20.20, point, 2? Round your answer, if necessary, to the nearest dollar. C=C=C, equals dollars
Mathematics
1 answer:
postnew [5]3 years ago
6 0

Answer:

<h2><em>$960,000</em></h2>

Step-by-step explanation:

The gross profit rate of the company is expressed as P = \dfrac{S - C}{S} where C is the cost of goods sold and S is the net sales. If the net sales S = $1,200,000, and gross profit ratio is 0.20, the cost of goods sold will be expressed as shown;

Making C the subject of the formula from the expression given.

P = \dfrac{S - C}{S}\\\\cross \ multiply\\\\SP = S-C\\\-C = SP-S\\\\C = S -SP\\

Substituting P = 0.20 and S = $1,200,000 into the resulting equation, we will have;

C = $1,2000,000 - 0.2($1,2000,000)\\C = $1,2000,000- 240,000\\ C = 960,000

<em>Hence the cost of goods sold is $960,000</em>

<em></em>

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Answer:

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3 years ago
Matthew invested $3,000 into two accounts. One account paid 3% interest and the other paid 8% interest. He earned 4% interest on
boyakko [2]

<u>Answer:</u>

<em>Mathew invested</em><em> $600 and $2400</em><em> in each account.</em>

<u>Solution:</u>

From question, the total amount invested by Mathew is $3000. Let p = $3000.

Mathew has invested the total amount $3000 in two accounts. Let us consider the amount invested in first account as ‘P’

So, the amount invested in second account = 3000 – P

Step 1:

Given that Mathew has paid 3% interest in first account .Let us calculate the simple interest (I_1) earned in first account for one year,

\text {simple interest}=\frac{\text {pnr}}{100}

Where  

p = amount invested in first account

n = number of years  

r = rate of interest

hence, by using above equation we get (I_1) as,  

I_{1}=\frac{P \times 1 \times 3}{100} ----- eqn 1

Step 2:

Mathew has paid 8% interest in second account. Let us calculate the simple interest (I_2) earned in second account,

I_{2} = \frac{(3000-P) \times 1 \times 8}{100} \text { ------ eqn } 2

Step 3:

Mathew has earned 4% interest on total investment of $3000. Let us calculate the total simple interest (I)

I = \frac{3000 \times 1 \times 4}{100} ----- eqn 3

Step 4:

Total simple interest = simple interest on first account + simple interest on second account.

Hence we get,

I = I_1+ I_2 ---- eqn 4

By substituting eqn 1 , 2, 3 in eqn 4

\frac{3000 \times 1 \times 4}{100} = \frac{P \times 1 \times 3}{100} + \frac{(3000-P) \times 1 \times 8}{100}

\frac{12000}{100} = \frac{3 P}{100} + \frac{(24000-8 P)}{100}

12000=3P + 24000 - 8P

5P = 12000

P = 2400

Thus, the value of the variable ‘P’ is 2400  

Hence, the amount invested in first account = p = 2400

The amount invested in second account = 3000 – p = 3000 – 2400 = 600  

Hence, Mathew invested $600 and $2400 in each account.

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Step-by-step explanation:


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Answer:

Following are the solution to the given points:

Step-by-step explanation:

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R={(0,1),(0,2),(0,3)(1,0),(1,1)(1,2),(2,0),(2,2),(3,0), (3,3)}

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