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joja [24]
3 years ago
10

Two numbers have a difference of 0.85 and a sum of 1 what are the numbers?

Mathematics
2 answers:
rjkz [21]3 years ago
5 0

let the two numbers be: x & y

x - y = 0.85

x + y = 1

Isolate the x. Subtract y from both sides

x + y (-y) = 1 (-y)

x = 1 - y

Plug in 1 - y for x in the other equation

x - y = 0.85

(1 - y) - y = 0.85

Simplify

1 - 2y = 0.85

Isolate the y. Note the equal sign. What you do to one side, you do to the other. Do the opposite of PEMDAS.

1 (-1) - 2y = 0.85 (-1)

-2y = -0.15

-2y/-2 = -0.15/-2

y = -0.15/-2

y = 0.075

Plug in 0.075 into one of the equations

x = 1 - y

x = 1 - (0.075)

x = 0.925

hope this helps

soldier1979 [14.2K]3 years ago
3 0
X - y = 0.85
x + y = 1
----------------add
2x = 1.85
x = 1.85/2
x = 0.925

x + y = 1
0.925 + y = 1
y = 1 - 0.925
y = 0.075

so ur 2 numbers are : 0.925 and 0.075
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Step-by-step explanation:

For this case we have defined the following function for the position of the particle:

x(t) = t^3 -6t^2 +9t -5 , 0\leq t\leq 10

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Part b

For this case we need to analyze the velocity function and where is increasing. The velocity function is given by:

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So from this we can see that we have two values where the function is equal to 0, t=3 and t=1, since our original interval is 0\leq t\leq 10 we need to analyze the following intervals:

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1

We have a minimum at t=2 since at this value w ehave the vertex of the parabola :

v_x =-\frac{b}{2a}= -\frac{-12}{2*3}= -2

And at t=-2 v(2) = -3 that represent the minimum for this function, we see that if we select two values let's say 1.5 and 1.75

v(1.75) =-2.8125< -2.25= v(1.5) so then the function sis decreasing on the interval 1<t<2

2

We see that the function would be increasing.

3

For this interval we will see that for any two points a,b with a>b we have f(a)>f(b) for example let's say a=3 and b =4

f(a=3) =0 , f(b=4) =9 , f(b)>f(a)

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Part c

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6t-12=0, t =2

And if we replace t=2 in the velocity function we got:

v(t) = 3(2)^2 -12(2) +9=-3

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