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sashaice [31]
2 years ago
8

Find the measures of the exterior angle.

Mathematics
1 answer:
Masja [62]2 years ago
3 0

Answer:126

Step-by-step explanation:

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Select all expressions that are equivalent to 64
pochemuha

Answer:

Step-by-step explanation:

What do you man what expressions or just expressions in general.

4 0
3 years ago
Given: \overline{AC} \perp \overline{BD} AC ⊥ BD and \overline{BD} BD bisects \overline{AC}. AC . Prove: \triangle ABD \cong \tr
Fofino [41]

Answer:

The Proof for

△ABD ≅ △CBD is below

Step-by-step explanation:

Given:

\overline{AC} \perp \overline{BD}

\overline{BD} \ bisects\  \overline{AC}

AD = CD      .........BD bisect AC

To Prove:

△ABD ≅ △CBD

Proof:

In  ΔABD  and ΔCBD  

BD ≅ BD              ....……….{Reflexive Property}

∠ADB ≅ ∠CDB    …………..{Measure of each angle is 90°( \overline{AC} \perp \overline{BD} )}

AD ≅ CD              ....……….{ \overline{BD} \ bisects\  \overline{AC} }

ΔABD  ≅ ΔCBD   .......….{By Side-Angle-Side Congruence test}  ...Proved

4 0
3 years ago
Which equation is the inverse of 5y+4= (x+3)² + 2?
Neko [114]
I think this is the answer to your question And also the solution

6 0
1 year ago
Which expression is equivalent to -1/2 (1/4 x - 3/8). SHOW WORK
Thepotemich [5.8K]

Answer:

A. -1/8 x + 3/16

Step-by-step explanation:

Distribute -1/2 over the parentheses

-1/2 ( 1/4 x - 3/8 )

-1/2 (1/4 x) - 1/2 (-3/8 )

multiply fractions to simplify

-1/8 x + 3/16

A is correct

8 0
2 years ago
1. ADEA has vertices D(8,4), E(2, 6), and F(3, 1). What are the vertices of the image after a dilation with a scale factor of 5
lubasha [3.4K]

Answer:

The vertices of the image are D' (40, 20), E' (10, 30), F' (15, 5)

Step-by-step explanation:

If the point (x, y) dilated by a scale factor k using the origin as a center of dilation, then its image is (kx, ky)

Let us use this rule to solve our question

∵ The vertices of ΔDEF are D (8, 4), E (2, 6), and F (3, 1)

∵ ΔDEF dilated by a scale factor 5

∴ k = 5

∵ The origin as the center of dilation

→ That means, multiply the coordinates of every point by 5

∴ D' = (8 × 5, 4 × 5)

∴ D' = (40, 20)

∴ E' = (2 × 5, 6 × 5)

∴ E' = (10, 30)

∴ F' = (3 × 5, 1 × 5)

∴ D' = (15, 5)

∴ The vertices of the image are D' (40, 20), E' (10, 30), F' (15, 5)

3 0
2 years ago
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