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3 years ago

What is the area of the figure? 118 in 48 in 128 in 108 in

Mathematics

1 answer:

Talja [164]3 years ago

5 0

Answer:

108 In

Step-by-step explanation:

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At 2 PM there were 13 seagulls on the beach. At 5 PM there were 70 seagulls. What is the constant rate of change

Olin [163]

The answer is 57 I hope I helped

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3 years ago

-2(6+s) Greater than or equal to -15 - 2s

Eddi Din [679]

Answer:

I'm leaning mostly towards C Because there is a solution, None of them are real numbers and if they were, S would = 5 Especially positive S

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3 years ago

The main goal of gambling companies is to

nataly862011 [7]

Answer:

make you interested in the game, so you spend more money

Step-by-step explanation:

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2 years ago

The Resource Conservation and Recovery Act mandates the tracking and disposal of hazardous waste produced at U.S. facilities. Pr

aniked [119]

Answer:

(a) $E(X) = 0.383$

The expected number in the sample that treats hazardous waste on-site is 0.383.

(b) $P(x = 4) = 0.000169$

There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

Step-by-step explanation:

Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.

N = 209

Only eight of these facilities treated hazardous waste on-site.

r = 8

a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?

n = 10

The expected number in the sample that treats hazardous waste on-site is given by

$E(X) = \frac{n \times r}{N}$

$E(X) = \frac{10 \times 8}{209}$

$E(X) = \frac{80}{209}$

$E(X) = 0.383$

Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.

b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site

The probability is given by

$P(x = 4) = \frac{\binom{r}{x} \binom{N - r}{n - x}}{\binom{N}{n}}$

For the given case, we have

N = 209

n = 10

r = 8

x = 4

$P(x = 4) = \frac{\binom{8}{4} \binom{209 - 8}{10 - 4}}{\binom{209}{10}}$

$P(x = 4) = \frac{\binom{8}{4} \binom{201}{6}}{\binom{209}{10}}$

$$ P(x = 4) = \frac{70 \times 84944276340}{35216131179263320}$

$P(x = 4) = 0.000169$

Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

8 0

3 years ago

Simplify the expression. Write the answer in scientific notation (7x10-6) (3x10-2

shtirl [24]

Answer:

21 X 10^-8 is the correct answer

Step-by-step explanation:

(7X3) X 10^(-6-2)

21 X 10^ -8

4 0

3 years ago