9/7 as a <span>mixed number is 1 2/7</span>
Answer:What are the equivalence classes of the equivalence relations in Exercise 3? A binary relation defined on a set S is said to be equivalence relation if it is reflexive, symmetric and transitive. An equivalence relation defined on a set S, partition the set into disjoint equivalence classes
Answer:
The answer is C, 220 units.
This question is incomplete, the complete question is;
For integers a, b and k, we know that a > 12, b < 20 and a < b. If b=7k, what is the value of k ?
Answer: the value of k = 2
Step-by-step explanation:
Given that;
a > 12
b < 20
a < b
If b = 7k
Now if k = 1 {b = 7k = 7}
b would be equal to 7 but b has to be greater than 20
IT CANT BE
if k = 2 { b = 7k = 14}
b would be equal to 14, a is greater than 12, b has to be less than b; 14 < 20,
a has to be less than than b ( 12 < 14 )
IT IS
if k = 3 {b = 7k = 21}
b would be equal to 21, so b is greater than 20 and a is less than 21
IT CANT BE
Therefore the value of k = 2
Answer:
b. only reason is correct
2.05 kg=2.05 ×1000 g
=2050 g
so the Assertion is incorrect